There will be one solution. To solve that:
1. Get the y alone by switching the places.
6x+y=2 > y=2-6x
-18x+3y=12 > 3y=12-18x > Then divide 3 on each number > y=4-6x
After doing that, you can solve this in graphing or algebra way.
Ima do the algebra way:
SO we have 2 system of equations. Now pick one equestion.
I will pick, y=2-6x. Now Ima replace the Y with the other equation y=4-6x >
4-6x=2-6x.
Now solve. And get > 0 aka Infinite Solution.
Answer:
1a) −24x^4−52x^3+198x^2+126x−325
2a) 14x^2+7x−41
3a) 30x^3+9x^2+32x−7
Step-by-step explanation:
The circle is open i think is the right answer i hope i got it right if not im very sorry :(
Answer:
D
Step-by-step explanation:
Let the total production order be X. The combined rate is thus x/36 orders per hour.
Now, we know that the three machines are working at the same constant rate. This means that individual rate for each of the machines will be x/36 divided by 3 and that gives x/108 per machine.
Now, we are having another machine coming at the same constant rate. This means we are adding an x/108 rate to the preexisting x/36.
The new total rate thus becomes x/108 + x/36 = 4x/108
Now we know that the total new rate is 4x/108. Since the total work doesn’t change and it is still x, the time taken to complete a work of x orders at a rate of 4x/108 order per hour would be x divided by 4x/108 and this is x * 108/4x = 108/4 = 27 hours