<h3>
Answer:</h3>
System
Solution
- p = m = 5 — 5 lb peanuts and 5 lb mixture
<h3>
Step-by-step explanation:</h3>
(a) Generally, the equations of interest are one that models the total amount of mixture, and one that models the amount of one of the constituents (or the ratio of constituents). Here, there are two constituents and we are given the desired ratio, so three different equations are possible describing the constituents of the mix.
For the total amount of mix:
... p + m = 10
For the quantity of peanuts in the mix:
... p + 0.2m = 0.6·10
For the quantity of almonds in the mix:
... 0.8m = 0.4·10
For the ratio of peanuts to almonds:
... (p +0.2m)/(0.8m) = 0.60/0.40
Any two (2) of these four (4) equations will serve as a system of equations that can be used to solve for the desired quantities. I like the third one because it is a "one-step" equation.
So, your system of equations could be ...
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(b) Dividing the second equation by 0.8 gives
... m = 5
Using the first equation to find p, we have ...
... p + 5 = 10
... p = 5
5 lb of peanuts and 5 lb of mixture are required.
Answer:
Um... Sure?
Step-by-step explanation:
Okay, 'll go to your questions...
Answer:
i think is y>X
Step-by-step explanation:
Answer:
Step-by-step explanation:
d(t)=-2t^2+9t+18
calculate the derivate : f'(t) = - 4t+9
f'(t) = 0 : - 4t+9= 0 so t = 9/4
the maximum value is f(9/4) = ....... continue
Answer:
6.10%
Step-by-step explanation:
For every round since we are choosing with equal probability, then the probability of choosing from either of the bags is 1/2
Here, this scenario is only possible when a particular bag has been chosen 10 times and the other bag has been chosen 6 times ( meaning a particular bag has been emptied and for a particular bag to be emptied, all of its content would have been picked)
Now on the 17th trial, an empty bag is chosen
Therefore the required probability will be;
16C0 * (1/2)^10 * (1/2)^6 * 1/2 = 0.0610 = 6.1%
