The kinetic energy transfers from the moving ball to the non-moving ball.
We develop an equation for the given situation by first writing the general equation for lines,
y = mx + b
Substituting to this given the values given above,
(1990) 430 = b
(2000) 400 = m(10) + 430
The value of m from the equation in 2000 is -3. Thus, the equation of that relates the variables is,
y = -3x + 430
5n-2=n+18
Move n to the other side
Sign changes from +n to -n
5n-n-2= n-n+18
5n-n-2= 18
4n-2= 18
Move -2 to the other side
Sign changes from -2 to +2
4n-2+2= 18+2
4n= 18+2
4n= 20
Divide by 4 for both sides
4n/4= 20/4
Answer: n=5
The answer is 4480 hope it helps
