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Dmitry [639]
3 years ago
8

Triangle ABC is right angled at A. if AB is 20 cm and AC is 15 cm then find length of BC

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:

BC = 25

Step-by-step explanation:

To find the length of BC you need to use the pythagorean theorem.  

a^{2} +b^{2}=c^{2}

There are two part to a triangle that need to be put into this equation.  The hypotenuse(c) and the legs(a, b).  The legs would be the side NEXT to the right angle.  The hypotenuse is ACROSS from the right angle.  In this equation we are looking for the hypotenuse.  It doesn't matter which letter the legs replace just remember that the hypotenuse alway has to be C.

20^{2} +15^{2} =c^{2}

Now you have to square the numbers then add.

400+225=c^{2}

625=c^{2}

Now find the square root of 625 to get rid of the squared in the C.

c = 25

Hope this helped.

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Calculate the area of triangle ABC with altitude CD, given A(−7, −1), B(−1, 5), C(0, 0), and D(−3, 3)
Snezhnost [94]

Answer:

A=25 (Rounded)

Step-by-step explanation:

The first step is to find the length of BA which is the base, then you have the find the length of CD, the hight.

To find the distance, you need to use the distance formula which is

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}} (It does not matter if A is x1 or is B is x1, it just has to remain consistent)

I am going to first find BA

d=\sqrt{\left({-7}-{-1}\right)^{2}+\left({-1}-{5}\right)^{2}}

Next, subtract accordingly

d=\sqrt{\left({-7}+{1}\right)^{2}+\left({-1}-{5}\right)^{2}}

d=\sqrt{\left({-6}\right)^{2}+\left({-6}\right)^{2}}

Once you do that, you want to square -6 and -6 which will give you

d=\sqrt{\left({36}\right)+\left({36}\right)}

Now add 36 with 36 which will leave you with

d=\sqrt{{72}}

Do that same thing for CD. If you did it right, you should be left with

d=\sqrt{{18}}

to find the area of a triangle, you must use the formula

A=\frac{B*H}{2}

The Base is \sqrt{{72}} (BA) and the Hight is \sqrt{{18}} (CD). substitute to get

A=\frac{\sqrt{{72}}*\sqrt{{18}}}{2}

Multiply the Base by the Hight to get

A=\frac{\sqrt{{1,296}}}{2}

Divide 1,296 by 2 to get

A=\sqrt{{648}}

Which is equal to

A=25.455844122715710878430397035775

Rounding it to the nearest whole number you get

A=25

Hope this helps. Feel free to ask any follow-up questions.

Have a good day! :)

6 0
3 years ago
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