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3 years ago

Find the slope of the line.

Mathematics

1 answer:

Marizza181 [45]3 years ago

5 0

Answer:

The slope is -5

Step-by-step explanation:

This line goes down 5 units and right 1 unit.

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*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago

PLEASE HELP ASAP!!! (No links)

marta [7]

Answer:

No it is not a solution

Step-by-step explanation:

To solve this, you should replace your (x,y) with (8,3)- 8 being your x value and 3 being your y value.

So this inequality, your y value is supposed to be bigger than the value of whatever 3x-4 equals.

So, your inequality should be 3>3(8)-4

3*8=24-4=20

So is 3>(greater than)20? No. Which then means that (8,3) is not a solution because it would make the inequality not true.

Hope this helps!

6 0

2 years ago

1. A snack bar sells two sizes of snack packs. A large snack pack is $8, and a

natali 33 [55]

answer

system : 8L+ 4S = 120

L + S = 20

There are 10 small packs and 10 large packs

step by step answer :

to form the two systems, we have to determine the catagories of the 2 equations : one for money and one for the no of packs

after forming the two equations we simply put the numbers in the same order put above on the calculator ( mode 5:1) and the calaculator will answer it in seconds . 10 small packs and 10 large packs.

To check your answer , substitute the letters with their values and if both equations gave you the same value at the end then your answer is correct!

7 0

3 years ago

I really need a quick answer! What is 8y + 12?

astra-53 [7]

Answer:

Step-by-step explanation:

To figure out what the value of y is, we must isolate the variable. To do this, we need to use the division property of equality which says that when you divide on one side of the equal sign, you must also divide on the other side.

8y/8 = y

12/8 = 1.5

This tells us the value of y, so next we have to apply this into the problem

8(1.5) = 12

12 + 12 = 24

24 is your answer

8 0

3 years ago

Read 2 more answers

Does the point (6, 2) satisfy the equation y = x - -4?

Advocard [28]

Answer:
No it does not.

Explanation:

If you plug in (6,2) into the equation it will become false

y = x - -4

2 = 6-(-4)
2 = 6 + 4
2 = 10

So the answer is no it does not.

5 0

3 years ago