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mart [117]
4 years ago
11

Determine whether the graph of the quadratic function y = –x^2 – 10x + 1 opens upward or downward. Explain.

Mathematics
1 answer:
REY [17]4 years ago
3 0
C. If the first coefficient is negative, then the graph opens downwards
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Solve the equation for a.<br><br> 3a+13.61=−9.43
snow_tiger [21]

Answer: a = -7.68

<u>STEPS:</u>

- Subtract 13.61 from both sides

- Simplify

- Divide both sides by 3

4 0
3 years ago
Lines J and k intersect at point Q and h is a straight line. What is the value of X ?
-BARSIC- [3]

Answer:

Step-by-step explanation:

Angles on a straight line add up to 180 so 180-135 equals 45. Vertically opposite angles are equal so the second angle inside the triangle equals 100. Henceforth, we can solve this equation:

x +45+100 = 180 (angles in triangle add up to 180)

x+145=180

x=35

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Hope this helps!

7 0
3 years ago
over the past ten years, the town's population doubled in size. the population is currently 12,000. what was the population ten
IceJOKER [234]
The population ten years ago was 6,000.

Because the population doubled you divide 12,000 by 2

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8 0
4 years ago
Read 2 more answers
Determine the value of the variables when simplifying and evaluating the expression (302)0 . What is the value of m in the simpl
maria [59]
Answers:
___________________________
1)    302⁰ = 1 .
___________________________
2)         (302)⁰ = 30m ;   Solve for "m" ;

          →   Replace:  "(302)⁰ " ;  with "1" and rewrite:

          →   1 = 30m ;

     <span>     ↔</span>   30m = 1 ;

      → Divide EACH SIDE of the equation by "30" ; to isolate "m" on one side of the equation; and to solve for "m" ;

      →   30m / 30 = 1 / 30  ;

      →    m = 1/30 ;  or, write as:  0.303333333333333333....  ; 
           →  round to:  0.3033 .
________________________________________________
3)   Again: 

           →  (302)⁰ = 1 .
________________________________________________
3 0
4 years ago
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The sum of two numbers is 1. The sum of
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Answer:

WAG KA MAG BRAINLY PANG BOBO LANG GUMAGAMIT NITO

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3 years ago
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