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LiRa [457]
3 years ago
6

A rectangular swimming pool is represented by x as the width and one less than twice the width as the length. If the area of the

swimming pool is given by 28 sq ft., which equation could be used to model the area of the swimming pool?
A. 28 = (2x - 1) + (x)
B. 28 = 2x -1•x
C. 28 = (2x - 1)(x)
D. 28x = 2x - 1
Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

C. 28 = (2x - 1)(x)

Step-by-step explanation:

Given :

There is a rectangular swimming pool.

Width of swimming pool is x

Length is  one less than twice the width

Area of the swimming pool is  28 sq ft.

To Find : Equation could be used to model the area of the swimming pool.

Solution:

Since we are given that Length is one less than twice the width.

And width is x (given)

So, length = 2x-1

Area of the swimming pool is  28 sq ft.

Now ,

Formula of area of rectangle : Length*Width

⇒28= (2x-1)(x)

So,  equation used to model the area of the swimming pool: 28= (2x-1)(x)

Hence Option c is correct.

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Standard form of a line passing through points (1, 3) and (-2, 5)
____ [38]

Answer:

<h2>2x + 3y = 33 </h2>

Step-by-step explanation:

As we move from (-2, 5) to (1, 3), x increases by 3 and y decreases by 2.

Hence, the slope of this line is m = rise / run = -2/3.

Start with the slope-intercept form y = mx + b.

Substitute 3 for y and 1 for x and -2/3 for m:

3 = (-2/3)(1) + b.

Remove fractions by mult. all three terms by 3:

9 = -2 + b, so b = 11, and y = (-2/3)x + 11

Again, mult. all three terms by 3:

3y = -2x + 33, or, in standard form,

<h2>2x + 3y = 33 </h2>
6 0
3 years ago
A substance with a half life is decaying exponentially. If there are initially 12grams of the substance and after 70 minutes the
dybincka [34]

Answer:

Step-by-step explanation:

Use the half life formula

N=N_0e^{kt} where N is the amount after decay, No is the initial amount, e is Euler's number, k is the decay constant, and t is the time in minutes. For us, the first equation looks like this:

7=12e^{k(70)} and we will solve that for k and then use that value of k in the second equation to find time.

Begin by dividing 7 by 12 to get

\frac{7}{12}=e^{k(70)} Now take the natural log of both sides since the natural log and that e are inverses. The e then disappears:

ln(\frac{7}{12})=k(70)

Plug the left side into your calculator and then set it equal to the right side, giving us:

-.5389965007=70k

Divide both sides by 70 to get the k value of

k = -.00769995

Now the second equation looks like this:

2=12e^{(-.00769995)t where t is our only unknown now that we know k.

Begin by dividing both sides by 12 to get

\frac{1}{6}=e^{-.00769995t and take the natural log of both sides again to eliminate the e:

ln(\frac{1}{6})=-.00769995t

Take care of the left side on your calculator to get

-1.791759469 = -.00769995t and divide both sides by -.00769995 to get

t = 232.697 minutes

4 0
2 years ago
I neeeeeeeeeeeeedddddd itttttttttt
LekaFEV [45]
5:
1/2 , 3/5 , .606 , 13/20 , 66%
6:
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8 0
2 years ago
NO LINKS PLEASE!
Nookie1986 [14]

Answer:

Set this up as a proportion.

54/n = 75/100

Now solve for n and finish from here.

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8 0
3 years ago
Read 2 more answers
About how much farther is it to drive than to walk directly from building A to building B? Round to the nearest whole number.
Sav [38]

Answer:

A. 183 meters

Step-by-step explanation:

Building A and building B are 500 meters apart. There is no road between them, so to drive from building A to building B, it is necessary to first drive to building C and then to building B. About how much farther is it to drive than to walk directly from building A to building B? Round to the nearest whole number. A) 183 meters B) 250 meters C) 366 meters D) 683 meters

Find distance BC

Cos (60°)=BC / AB (Adjacent divided by the hypotenuse)

Cos (60°)=1/2

BC=a

AB=500

Cos (60°)=BC / AB

1/2=a/500

1/2 * 500=a

250=a

a=250m

Find distance AC

Sin(60°)=AC/AB (opposite side divided by hypotenuse)

Sin(60°)=√3/2

AC=b

AB=500

Sin(60°)=AC/AB

√3/2=b/500

√3/2 * 500=b

250√3=b

b=433m

Distance AC and BC=AC+BC

433m+250m=683m

Subtract the distance AB from AC+BC

= 683m - 500m

=183m

Answer is A. 183 meters

8 0
3 years ago
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