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LiRa [457]
3 years ago
6

A rectangular swimming pool is represented by x as the width and one less than twice the width as the length. If the area of the

swimming pool is given by 28 sq ft., which equation could be used to model the area of the swimming pool?
A. 28 = (2x - 1) + (x)
B. 28 = 2x -1•x
C. 28 = (2x - 1)(x)
D. 28x = 2x - 1
Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

C. 28 = (2x - 1)(x)

Step-by-step explanation:

Given :

There is a rectangular swimming pool.

Width of swimming pool is x

Length is  one less than twice the width

Area of the swimming pool is  28 sq ft.

To Find : Equation could be used to model the area of the swimming pool.

Solution:

Since we are given that Length is one less than twice the width.

And width is x (given)

So, length = 2x-1

Area of the swimming pool is  28 sq ft.

Now ,

Formula of area of rectangle : Length*Width

⇒28= (2x-1)(x)

So,  equation used to model the area of the swimming pool: 28= (2x-1)(x)

Hence Option c is correct.

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Complete the table for the following function<br> y=(1/3)^x
Bumek [7]

x=-3 then y= 27

x= -2 then y= 9

x=2 then y: y=\frac{1}{9}

x=3 then y: y=\frac{1}{27}

The graph of the function decreases from left to right.

Option C is correct.

Step-by-step explanation:

We are given the function: y=(\frac{1}{3})^x

and we need to fill the table

if x = -3 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^-3

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{\frac{1}{27}}\\y=27

if x = -2 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^-2

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{\frac{1}{9}}\\y=9

if x = 2 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^2

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{9}

if x = 3 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^3

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{27}

So, x=-3 then y= 27

x= -2 then y= 9

x=2 then y: y=\frac{1}{9}

x=3 then y: y=\frac{1}{27}

Graph of the function is shown in figure attached.

The graph of the function decreases from left to right.

Option C is correct.

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

7 0
4 years ago
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