9w = -54

Select the improper fraction: 3/13 5/16 16/11 9/12

n200080 [17]

16/11
Hope this helps! :)

8 0

3 years ago

Read 2 more answers

What is 18.386 rounded to the nearest Hundred

jonny [76]

This will be 18.39, 6 is higher than 5, so the 8 is going higher so it's a 9 and you will get 18.39

8 0

3 years ago

Jin tried to evaluate 5 + 2 x 9 step-by-step.

Zigmanuir [339]

Answer:

5 + 2 x 9

Step 1 = 7 x 9

Step 2 = 63

Step-by-step explanation:

= 5 + 2 x 9

= 5 + ( 2 x 9 )

= 5 + 18

= 23

Step 2 = 7 x 9

= 63

Step 3 = 63

C. jin did not make a mistake

Sorry i'm wrong :)

4 0

4 years ago

A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple

devlian [24]

Answer:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=46$ represent the mean height for the sample

$s=5.148$ represent the sample standard deviation

$n=5$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:

Null hypothesis: $\mu = 40$

Alternative hypothesis: $\mu \neq 40$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

6 0

4 years ago

How do yo work out 9.1 divided by 3575

EastWind [94]

9.1/3575
use long division like this
 _0._________
3575|91.000000

we find how many of 3575 fit into the 91
it's too big so we go farther
how many 3575 go into 910
too big so we go farther
how many 3575 go into 9100
the answer is 2 so put that in the correct place and mulitply that and put that in the correct place. then we subtract

 _0.02_________
3575|91.000000
 -71.50
 19.50
bring down the next number
find how many go into 19.500
the answe ris 5

 _0.025_________
3575|91.000000
 -71.50
 19.500
 -17.875
 1.625

bring down he next zero ( I fast forward and skip steps for convinience)

 __
 _0.025455_________
3575|91.000000
 -71.50
 19.500
 -17.875
 1.6250
 -1.4300
 .19500
 -.17875
 16250
 -14300
and so on untill infinity so the answe ris 0.0254555555555555 (enless fives)

8 0

3 years ago