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ValentinkaMS [17]
3 years ago
8

What is the area of rectangle ABCD?

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
5 0

Answer:

240

Step-by-step explanation:

The length is 20 and the width is 12 so you just multiply 20 and 12 together which is 240

Lina20 [59]3 years ago
4 0

Answer:240inc

Step-by-step explanation:

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Which compound inequalities have the solution set represented by the given graph? Check all that apply
Contact [7]

We check with each options

'Or' represents the intersection of two graphs

'And' represents two separate graphs'

We have two separate shaded part in the given graph

So we ignore the options that has 'and' in between

LEts check first  and second option

\frac{x}{2}=13

Simplify the first part and second part

multiply both sides by 2 .

x < 2  or  4x - 2 > = 26

solve 4x-2 > = 26

add 2 on both sides and then divide both sides by 4

4x >= 28

x >= 7

So solution is x<2 or x>=7 . that is the graph on number line

Lets check with second option

3x-3<3  or  2x+8>=22

add 3 on both sides

3x < 6

divide both sides by 3

so x< 2

2x+8>=22

subtract 8 on both sides

2x >= 30

divide both sides by 2

x >= 15

x<2  or x>=15 that does not satisfies the graph

So option A is correct



7 0
3 years ago
Read 2 more answers
A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)
DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

Speed=\frac{distance}{time}

in this problem we have

distance=400\ m \\time=120\ sec

substitute in the formula

Speed=\frac{400}{120}

Speed=3.5\frac{m}{sec}

therefore

<u>the answer Part a) is</u>

the speed is equal to 3.5\frac{m}{sec}

<u>Part b) </u>Find the velocity

we know that

<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

magnitude=3.5\frac{m}{sec}

direction=North\ East\ (NE)

therefore

<u>the answer Part b) is</u>

the velocity is 3.5\frac{m}{sec}\ North\ East\ (NE)

Part c)

we know that

the acceleration is equal to the formula

a=\frac{V2-V1}{t2-t1}

in this problem we have

V2=0 \\V1=3.5\frac{m}{sec}

t2=15\ sec\\t1=0

substitute in the formula

a=\frac{0-3.5}{15-0}

a=-\frac{3.5}{15}\frac{m}{sec^{2}}

a=-\frac{7}{30}\frac{m}{sec^{2}}

therefore

<u>the answer Part c) is</u>

the acceleration is -\frac{7}{30}\frac{m}{sec^{2}}

This is an example of negative acceleration

7 0
3 years ago
Read 2 more answers
Please help and explain your work
Ilia_Sergeevich [38]

Answer:

416mm³

Step-by-step explanation:

Volume of rectangular prism

= 10.4mm × 5mm × 8mm

= 416mm³

6 0
2 years ago
Suppose the equation of the axis of symmetry for a quadratic function is x = 3 and one of the x-intercepts is 8. What is the oth
soldi70 [24.7K]

Answer:

-2

Step-by-step explanation:

The axis of symmetry divides the quadratic exactly in half. If one x-intercept is 8, then the other will be the same distance on the other side of it. 8 is 5 from 3 where the axis of symmetry is. So 3-5 = -2. -2 will be the other intercept.

8 0
3 years ago
Derive the formula for the area of a sector, and then use it to choose all that are correct.
Marina CMI [18]

Answer:

Part A) A_s=\frac{\pi r^{2}}{360^o}{\theta}

Part B) option 1,option 4

Step-by-step explanation:

Part A) Derive the formula for the area of a sector

we know that

The area of circle is equal to

A=\pi r^{2}

The area of circle subtends a central angle of 360 degrees

so

using proportion

Find out the area of a sector  A_s  by a central angle of ∅ degrees

\frac{\pi r^{2}}{360^o}=\frac{A_s}{\theta}

A_s=\frac{\pi r^{2}}{360^o}{\theta}

Part B) Verify each case

case 1) we have

radius = 5 cm

angle = 120°

area = 26.2 cm 2

Find the area of the sector and then compare with the value of the given area

assume

\pi=3.14

substitute the given values

A_s=\frac{(3.14)(5)^{2}}{360^o}{120^o}

A_s=26.2\ cm^2

so

The given value of area is correct

case 2) we have

radius = 4 cm

angle = 105°

area = 16.7 cm 2

Find the area of the sector and then compare with the value of the given area

assume

\pi=3.14

substitute the given values

A_s=\frac{(3.14)(4)^{2}}{360^o}{105^o}

A_s=14.7\ cm^2

so

The given value of area is not correct

case 3) we have

radius = 6 cm

angle = 85°

area = 23.7 cm 2

Find the area of the sector and then compare with the value of the given area

assume

\pi=3.14

substitute the given values

A_s=\frac{(3.14)(6)^{2}}{360^o}{85^o}

A_s=26.7\ cm^2

so

The given value of area is not correct

case 4) we have

radius = 7

angle = 75°

area = 32.1 cm 2

Find the area of the sector and then compare with the value of the given area

assume

\pi=3.14

substitute the given values

A_s=\frac{(3.14)(7)^{2}}{360^o}{75^o}

A_s=32.1\ cm^2

so

The given value of area is correct

5 0
3 years ago
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