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insens350 [35]
4 years ago
15

Which expression is equal to 6/√5

Mathematics
1 answer:
Blizzard [7]4 years ago
7 0

Answer:

2.683281573

Step-by-step explanation:

Did it on a notebook and check if it was correct on my calculator. Please like and rate my answer.

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Find cot theta if csc theta= the square root of 5/2 and tan theta>0
Nostrana [21]
Since \cot^2\theta+1=\csc^2\theta, you have

\cot^2\theta=\left(\dfrac{\sqrt5}2\right)^2-1=\dfrac14
\cot\theta=\pm\sqrt{\dfrac14}=\pm\dfrac12

Since \tan\theta>0, and \cot\theta=\dfrac1{\tan\theta}, you know that \cot\theta is also positive, which means

\cot\theta=\dfrac12
3 0
3 years ago
Write expanded form.one million,three hundred forty five thousand,eight hundred twenty
NARA [144]
1,000,000+ 300,000 +40,000+5,000+800+20 = 1,345,820
4 0
4 years ago
Read 2 more answers
Solving polynomial equations by factoring Solve: 1/2x^2+5x+25/2=0 Full explanation please, thanks
asambeis [7]

Answer:

x=-5

Step-by-step explanation:

1/2x^2+5x+25/2=0

Multiply each side by 2 to clear the fractions

2*(1/2x^2+5x+25/2)=0*2

Distribute

x^2+10x+25=0

What two numbers multiply together to give us 25 and add together to give us 10

5*5 = 25

5+5 =10

(x+5) (x+5) =0

Using the zero product property

x+5 =0  x+5 = 0

x+5-5= 0-5    x+5-5 =0-5

x=-5  x=-5

x=-5

3 0
4 years ago
Helppppppp...?????????????????????
Angelina_Jolie [31]

Answer:

144(3/4)^1-n

Step-by-step explanation:

This is a geometric sequence, so if you divide 192 by 144 you will find that the common ratio r is 4/3. This would make the equation an=144(4/3)^n-1. However, that's not one of the options. If you plug in some numbers, you can see that 3/4 (the reciprocal of 4/3) can work as well if it's 3/4^1-n. 4/3^-1=3/4 and n-1(-1)=1-n

4 0
3 years ago
Solve in radians help plz
PIT_PIT [208]
I think we can use the identity  sin x/2  = sqrt [(1 - cos x) /2]

cos x -  sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1

cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) =  cos x - 1   Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1

cos^2 x - 0.5 cos x - 0.5 = 0 

cos x = 1 , -0.5

giving x = 0 , 2pi, 2pi/3,  4pi/3  ( for  0  =< x <= 2pi)

because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.

The last 2 results dont fit so the answer is  x = 0 , 2pi Answer
5 0
3 years ago
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