Someone help me please :(
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The base of log is 10. So raising both sides to 10, we get:
S, rounding of to nearest hundredth, the value of x in the equation 0.94 = log(x) comes out to be 8.71.
S, rounding of to nearest hundredth, the value of x in the equation 0.94 = log(x) comes out to be 8.71.
Answer:
11
Step-by-step explanation:
Hello,
Given the original number n.
Multiply the number by 9.
Add 99.
Divide this sum by 9.
Subtract the original number, n, from the quotient.
Thank you.
The derivative of 1/logx is With the chain rule.
1log(x)=log(x)−1 is ,= -1xlog(x)2 .
The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".
The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.
Read more about derivatives;
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