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slavikrds [6]
3 years ago
9

Half the marbles in a bag are red, 1/6 of the marbles are blue, and the remaining 8 marbles are white how many total marbles are

in the bag
Mathematics
1 answer:
Gemiola [76]3 years ago
7 0

Hey there! I'm happy to help!

Let's represent the total number of marbles with the variable t. We have the following information.

1/2t+1/6t+8=t (1/2 of total are red, 1/6 of total are blue, 8 are white, add them up to get total)

Now, we solve for t.

1/2t+1/6t+8=t

We combine like terms.

2/3t+8=t

We subtract t from both sides.

-1/3t+8=0

We subtract 8 from both sides.

-1/3t=-8

We divide both sides by -1/3.

t=24

Therefore, there ae 24 total marbles in the bag.

Have a wonderful day! :D

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A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
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<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1

Which is also true.

<u>At, </u>

<u>n = 3</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

This is also true at the given value of 'n'.

<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

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