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2 years ago

Polynomial Basics

Mathematics

1 answer:

Rzqust [24]2 years ago

5 0

Exponential is the answer okau

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In which situation do the quantities combine to make 0?

SOVA2 [1]

Answer: A

Step-by-step explanation: If he is in debt 10$ and later pays back the 10$ he is at 0 total debt (Equation: -10x + 10x = 0

(Debt means : he owes money). (Brainliest Please)

4 0

3 years ago

A salesperson gets a commission of $1400 for the first $10,000 of sales, and then $700 for each additional $10,000 or partial of

Alenkasestr [34]

Answer:

$s(65,000)= \$ 4,900$

Step-by-step explanation:

$s(x)$ represents the commission on $x$ dollars of sales.

For the first $10,000 of sales, the commission is $1400.

For each additional $10,000, the commission is $700.

The total value is $65,000.

The first $10,000 implies a commission of $1400.

The rest is $55,000, which represents 5 times $10,000 and $5,000. The additional commission is 5 times $700, which is $3500.

Therefore, the total commission for the sale of $65,000 is $4,900.

$s(65,000)= \$ 4,900$

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4 years ago

Plzzzzz help me i really need this!!!

Damm [24]

Answer:

2.7

Step-by-step explanation:

8 0

3 years ago

Solve the equation.<br><br> 5p^2-p+4

Furkat [3]

Either c or d not sure

8 0

3 years ago

A smog alert has been called in a certain area of Los Angeles County in which there are 50 industrial rms. An inspector will vis

damaskus [11]

Answer:

Part (A) The required PMF is: $P(X=x)=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}$

Part (B) $B(x;n,p)=\binom{10}{x}(0.3)^x(1-0.3)^{10-x}$

Step-by-step explanation:

Consider the provided information.

There are 50 industrial rms. An inspector will visit 10 randomly selected rms to check for violations of regulations.

Part (A)

15 of the rms are actually violating at least one regulation.

Let X is the number of firms violate at least one regulation from 10 randomly selected rms to check for violations of regulations out of 50 firms of which 15 5 of the rms are actually violating.

Therefore, $X\sim Hypergeom(n=10, M=15\ and\ N=50)$

We need to determine probability mass function.

$P(X=x)=Hyper(x; n=10, M=15, N=50)\\=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}$

Hence, the required PMF is: $P(X=x)=\frac{\binom{15}{x}\binom{50-15}{10-x}}{\binom{50}{10}}$

Part (B) If there are 500 rms in the area, of which 150 are in violation, approximate the pmf of part.

Here N=500 so find the probability of p as shown below:

$p=\frac{150}{500} =0.3$ and n=10

$B(x;n,p)=B(x;10,0.3)\\=\binom{10}{x}(0.3)^x(1-0.3)^{10-x}$

5 0

4 years ago