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Pani-rosa [81]
3 years ago
8

Use the formula A = x2 to solve for the area of the square. x = 1 4/5

Mathematics
1 answer:
lara31 [8.8K]3 years ago
4 0
A=x²
Substitute x with 1 4/5 or 9/5
A=(9/5)²
A=(9/5(9/5)
A=81/25
A=3.24. As a result, area of the square is 3.24 square units. Hope it help!
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What is the probability that the product of two dice is greater than<br> 15 on two separate rolls?
ratelena [41]

Answer:

25/324

Step-by-step explanation:

Make a table of possible products:

\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&1&2&3&4&5&6\\2&2&4&6&8&10&12\\3&3&6&9&12&15&18\\4&4&8&12&16&20&24\\5&5&10&15&20&25&30\\6&6&12&18&24&30&36\end{array}\right]

Of the 36 results, 10 are greater than 15.

The probability the product is greater than 15 on a single roll is 10/36 = 5/18.

The probability the product is greater than 15 on two rolls is (5/18)² = 25/324.

4 0
3 years ago
One lunch table can hold 10 students. There are 60 students in 3rd grade. How many lunch tables are needed so that every student
Sladkaya [172]

Answer:

6 lunch tables

Step-by-step explanation:

Since one lunch table can hold 10 students and 60 students are needed to hold,

60 ÷ 10 = 6 lunch tables

5 0
3 years ago
Read 2 more answers
For positive acute angles A and B, it is known that cos A= 20/29 and tan B= 11/60. Find the value of cos(A + B) in simplest form
jek_recluse [69]

Answer:

\displaystyle \cos(A + B) =\frac{969}{1769}

Step-by-step explanation:

We are given that:

\displaystyle \cos A=\frac{20}{29}\text{ and } \tan B=\frac{11}{60}

Where A and B are positive acute angles.

And we want to find cos(A + B).

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using this information, find the opposite side with respect to Angle A:

o=\sqrt{29^2-20^2}=21

Tangent is the ratio of the opposite side to the adjacent side. Find the hypotenuse with respect to Angle B:

h=\sqrt{11^2+60^2}=61

In summary:

With respect to Angle A, the adjacent side is 20, opposite is 21, and the hypotenuse is 29.

With respect to Angle B, the adjacent side is 60, the opposite is 11, and the hypotenuse is 61.

We can rewrite our expression as:

\displaystyle \cos(A+B)=\cos A\cos B-\sin A\sin B

Using the above information, substitute in the appropriate values. Note that since A and B are positive acute angles, all trigonometric values will be positive. Hence:

\displaystyle \cos(A + B)=\left(\frac{20}{29}\right)\left(\frac{60}{61}\right)-\left(\frac{21}{29}\right)\left(\frac{11}{61}\right)

Simplify:

\displaystyle \cos(A + B) =\frac{1200-231}{1769}=\frac{969}{1769}

3 0
3 years ago
Solve the system of equations. 4x+2y+5z=8 5x+3y+4z=9 6x+3y+3z=3
Alchen [17]

Answer:

x = -4, y = 7,  z = 2.

Step-by-step explanation:

4x + 2y + 5z = 8......(1)

5x + 3y + 4z = 9......(2)

6x + 3y + 3z = 3......(3)

Subtract:  equation (2) - equation (3):

-x + z = 6 ........(4)

Multiply   (1) by 3 and (2) by 2:

12x + 6y + 15z = 24 .........(5)

10x + 6y + 8z = 18 ...........(6)

Subtract: (5) - (6):

2x + 7z = 6..............(7)

Multiply  equation (4) by 2:

- 2x + 2z = 12.........(8)

Add (7) + (8):

9z = 18 , so  z = 2.

Substitute for z in equation (4)

-x + 2 = 6

-x =  4 so x = -4.

Now find y by substituting in equation (1):

4(-4) + 2y + 5(2) = 8

2y =  8 + 16 - 10 = 14

y = 7.

3 0
3 years ago
Recall that the perimeter of a square is 4 times as large as the length of one of the sides of the square. Let x represent the l
Tcecarenko [31]
  • The required function formula for the function "f" is f(x) = 4x
  • Since the side length of the square cannot be positive, hence the domain will be values from 0 and above i.e. Domain = 0≤x≤∞
  • The range of the function will be 4≤f(x)≤∞

The perimeter of a square is expressed according to the formula:

P = 4L

P is the perimeter of the square

L is the side length of the square

Given the following

Perimeter is y

Length is x

The function that represents the statement is expressed as y=4x

The required function formula for the function "f" is f(x) = 4x

The domain of the function is the value of the input value for which the function exists

  • Since the side length of the square cannot be positive, hence the domain will be values from 0 and above i.e. Domain = 0≤x≤∞

The range of the function is the value of the output value f(x) for which the function exists, hence;

  • The range of the function will be 4≤f(x)≤∞

Learn more here: brainly.com/question/20838649

3 0
3 years ago
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