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LenaWriter [7]
3 years ago
13

HELPPP im running out of time hjhjhdkw

Mathematics
2 answers:
Eduardwww [97]3 years ago
6 0
It’ll be the bottom left
Anon25 [30]3 years ago
4 0

Answer:

lol put more points 8 too little bit

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Add or subtract write the ansewr in simplest form 1/4+1/10
astra-53 [7]

Answer:

7/20

Step-by-step explanation:

7 0
3 years ago
What is the coefficient of the fourth term in the expansion of (x - y)^6?
Zarrin [17]
<span>If you're aware of the binomial theorem, you have that:
</span>(x-y)^6=\sum_{k=0}^{6}\binom{6}{6-k}x^k(-1)^{6-k}y^{6-k}
(x-y)^6=\sum_{k=0}^{6}\binom{6}{k}x^k(-1)^{k}y^{6-k}

The fourth term is then the case k=3, from which:
c_{3}=\binom{6}{3}x^3(-1)^3y^3= \frac{6!}{3!(6-3)!} * (-x^3y^3)=- \frac{720}{36}x^3y^3=-20x^3y^3
3 0
3 years ago
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Mr. Ramirez class is playing a game in which students in a batch sticky notes that have an equivalent expression how can you sor
nadya68 [22]

Brackets & Non Brackets

Step-by-step explanation:

You could sort them into equations with brackets and equations without brackets

7 0
3 years ago
Explain how to divide two rational numbers
Liono4ka [1.6K]
if they're both even, divide by two. rational numbers presume reduced fractions. Dividing rational numbers. If two numbers you want to divide, flip the 2nd and multiply.
7 0
3 years ago
Solve each quadratic equation by completing the square. Give exact answers--no decimals.
alexandr1967 [171]

Answer:

x_1= -3+4(\sqrt{2})i\\\\x_2 = -3-4(\sqrt{2})i

Step-by-step explanation:

In this problem we have the equation of the following quadratic equation and we want to solve it using the method of square completion:

x ^ 2 + 6x +41 = 0

The steps are shown below:

For any equation of the form: ax ^ 2 + bx + c = 0

1. If the coefficient a is different from 1, then take a as a common factor.

In this case a = 1. Then we go directly to step 2

2. Take the coefficient b that accompanies the variable x. In this case the coefficient is 6. Then, divide by 2 and the result squared it.

We have:

\frac{6}{2} = 2

(\frac{6}{2}) ^ 2 = 9

3. Add the term obtained in the previous step on both sides of equality

x ^ 2 + 6x + 9 = -41 +9

4. Factor the resulting expression, and you will get:

(x + 3) ^ 2 =-32

Now solve the equation:

Note that the term (x + 3) ^ 2 is always > 0 therefore it can not be equal to -32.

The equation has no solution in real numbers.

In the same way we can find the complex roots:

(x + 3) ^ 2 = -32\\\\(x + 3) = \±\sqrt{-32}\\\\x = -3 \± \sqrt{-32}\\\\x = -3 \± 4(\sqrt{2})i\\\\x_1= -3+4(\sqrt{2})i\\\\x_2 = -3-4(\sqrt{2})i

6 0
3 years ago
Read 2 more answers
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