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4 years ago

Solve the equation 7m-5-13m=25 by combining like terms. Show all work please need asap

2 answers:

7 0

You must combine like terms.
First add 7m and -13m which makes -6m. That makes the equation
-6m - 5 =25.
Then add 5 on both sides, which makes -6m = 30.
Finally divide -6 on both sides and the answer will be
m= -5

Strike441 [17]4 years ago

4 0

You subtract 7m and 13m which would give you -6m after you have -6m - 5= 25 then you add 5 which gives you 30 you then you divide that by -6 which gives you m=-5

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Intercontinental, Inc., uses a perpetual inventory system. Consider the following information about its inventory: July 1, purch

salantis [7]

Answer:

Using weighted average, the cost of goods sold for the sale of 23 units on July 31 is $2,504.70, and the inventory balance at July 31 is $ 1,306.90.

Step-by-step explanation:

Since Intercontinental, Inc., uses a perpetual inventory system, and on July 1, purchased 10 units for $ 910 or $ 91 per unit; on July 3, purchased 15 units for $ 1,590 or $ 106 per unit; on July 14, it sold 20 units; on July 17, purchased 20 units for $ 2,300 or $ 115 per unit; on July 28, purchased 10 units for $ 1,190 or $ 119 per unit; and on July 31, sold 23 units, to determine the average costs and the inventory balance as of July 31, the following calculations must be performed:

(910 +1590 + 2300 + 1190) / (10 + 15 + 20 + 10) = X

5990/55 = X

108.90 = X

108.90 x 23 = 2504.7

(55 x 108.9) - (43 x 108.9) = X

5990 - 4683.10 = X

1306.90 = X

Using weighted average, the cost of goods sold for the sale of 23 units on July 31 is $ 2504.70, and the inventory balance at July 31 is $ 1,306.90.

8 1

3 years ago

Read 2 more answers

Answer the 3 screenshotted questions below. 30 points!

Triss [41]

Answer:

13. $36a^2b^4$ π

14. $16x^3y^4$ π

15. $-\frac{c^3}{4a^7b^3}$

Step-by-step explanation:

13.

A = π * $r^2$

r = $6ab^2$

A = π* $(6ab^2)^2$

A = π * $(6ab^2)(6ab^2)$

A = π * $36a^2b^4$

A = $36a^2b^4$ π

14.

V = π * $r^2$ * h

r = $2x$

h = $4xy^4$

V = π * $(2x)^2$ * $4xy^4$

V = π * $4x^2$ * $4xy^4$

V = π * $16x^3y^4$

V = $16x^3y^4$ π

15. $\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$ = $-\frac{c^3}{4a^7b^3}$

$\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$

$\frac{a^{-4}}{-4a^3b^5c^{-3}}$

$\frac{b^2}{-4^{3+4}b^5c^{-3}}$

$\frac{b^2}{-4^7b^5c^{-3}}$

$\frac{1}{-4a^7b^{5-2}c^{-3}}$

$\frac{1}{-4a^7b^3c^{-3}}$

$\frac{c^3}{-4a^7b^3}$

$-\frac{c^3}{4a^7b^3}$

Hope this helps!

3 0

3 years ago

Convert to a decimal: 52% 0.052 5.20 O 52 .0052

scoundrel [369]

Very interesting question, i’m happily here to answer it for you The answer you might be looking for is
decimal: 0.052
Fraction:13/250
Percentage: 5.2%

Have a blessed day God bless.

4 0

3 years ago

Read 2 more answers

I really need help with this Triangle problem.

dedylja [7]

Answer:

Step-by-step explanation:

Here we use SOHCAHTOA

Seeing as we have the hypotenuse and we are working to find out the opposite, we use SOH

Sin(x)= Opposite/Hypotenuse

Sin(45) = x/ $12\sqrt{2} \\$

×12 root 2

sin(45) times 12 root 2= 12

x=12

3 0

3 years ago

(Ignore that I selected an answer) Can someone pls help me

Nutka1998 [239]

Answer: B
X-8=-5
+8 +8
X=3

7 0

3 years ago