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lbvjy [14]
3 years ago
7

PLEASE HELP I WILL GIVE BRAINALIST!!!!

Mathematics
1 answer:
Zolol [24]3 years ago
7 0

9514 1404 393

Answer:

  y = 2x +5

Step-by-step explanation:

We can use the slope formula to find the slope of AB, which is the same as the slope of the parallel line. Then, we can use the point-slope equation for a line to find the desired equation.

  m = (y2 -y1)/(x2 -x1)

  m = (-8 -2)/(-1 -4) = -10/-5 = 2

__

  y -y1 = m(x -x1) . .  point-slope form of equation for a line

  y -5 = 2(x -0) . . . . fill in m=2, (x1, y1) = (0, 5)

  y = 2x +5 . . . . . . . rearrange to slope-intercept form

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Please help me need help me please please help me
Reil [10]

9514 1404 393

Answer:

  (3)  y = (x -3)²

Step-by-step explanation:

Try the first value of x in each function:

  (1)  y = 3² -3 ≠ 0

  (2)  y = (3 +3)² ≠ 0

  (3)  y = (3 -3)² = 0 . . . . . . matches the table value for f(3)

  (4)  y = 3² +3 ≠ 0

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The only viable choice is (3).

5 0
3 years ago
Help meeeeeeeeeeeee<br><br><br><br><br><br>2/3u. 4/2u².3=<br>​
Firdavs [7]

Answer:

4u³

Step-by-step explanation:

2/3u × 4/2u² = 4/3u³

4/3u³ × 3/1 = 4u³

6 0
3 years ago
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Does anyone know this it sounds simple but there is usually something else to it so I’m not sure.
Artist 52 [7]
16 because 8 rooms have 8-11, 5 rooms have 4-7, and 3 rooms have 0-3 guests.
8 0
3 years ago
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(2 * 15x) + (2 * 10)
yan [13]

Answer:

(2 \times 15x) + (2 \times 10) \\  = 30x + 20 \\  = 10(3x + 2)

6 0
3 years ago
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If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?
Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

m\angle B=\sin ^{-1}(\dfrac{m}{n})

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times h

Where, b is the base and h is the height of the triangle.

Area=\dfrac{1}{2}\times a\times h

The area of the triangle ABC is D.

D=\dfrac{1}{2}\times a\times h

2D=ah

\dfrac{2D}{a}=h                  ...(i)

In a right angle triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin B =\dfrac{h}{c}

\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}              [Using (i)]

\sin B =\dfrac{2D}{ac}

m\angle B =\sin ^{-1}\dfrac{2D}{ac}            ...(ii)

We have,

m\angle B=\sin ^{-1}(\dfrac{m}{n})          ...(iii)

On comparing (ii) and (iii), we get

m=2D

n=ac

Therefore, the required values are m=2D, n=ac.

6 0
3 years ago
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