Quadrant III dhdidjeoejdosjsosjdisjehussihsisisisjjsisisis
Answer:
Step-by-step explanation:
1. JK ∥ LM, KL ∥ MN Given
2. ∠KJL ≅ ∠MLN; ∠KLJ ≅ ∠MNL c. Corresponding Angles
3. JK ≅ LM Given
4. ∆JKL ≅ ∆LMN e. AAS
Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.
For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3
We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3
So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3
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Find the slope of the line first:
5x - 2y = -6,
y = (5/2)x + 3;
Since we need a line that's perpendicular, m = - (2/5).
The only equation that has the slope of this m is 2x + 5y = -10;
Download photomath and it will give u step by step instructions