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amm1812
3 years ago
8

What number is 33% of 360? Round to nearest tenth if necessary. Show work

Mathematics
2 answers:
Alex777 [14]3 years ago
6 0
360 x 33% = 118.8 rounded to nearest tenth = 120

360/3=120 the reason you would divide 360 by 3 is because it is 30% of 360 which would give you the answer if you round 33% to the nearest tenth of 30% 
Sergio [31]3 years ago
4 0
33% of 360 33%01/3 360/3=120 33% of 360 is 120 I hope that's help !
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I really need help so please help me out
AnnyKZ [126]

Answer:

The answer is option 2.

Step-by-step explanation:

Given that the TU and UF added up together to form a length of 32. In order to find TU, you have to subtract length of UF from 32 :

TU + UF = 32

TU + 20 = 32

TU = 32 - 20

TU = 12

4 0
2 years ago
Help!!!! ASAP!!!!!!!!!!!!!!!!
Hitman42 [59]

Answer:

p=15

Step-by-step explanation:

24/8=3

3x5=15

4 0
2 years ago
Read 2 more answers
Please help! Consider the given circle with the shaded sector xy and central angle 225. The circumference is 30 units
OleMash [197]

\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=30\pi \end{cases}\implies 30\pi =2\pi r\implies \cfrac{30\pi }{2\pi }=r\implies \boxed{15=r} \\\\[-0.35em] ~\dotfill

\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=15\\ \theta =225 \end{cases}\implies \widehat{XY}=\cfrac{(225)\pi (15)}{180}\implies \boxed{\widehat{XY}\approx 58.90} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad A=\pi (15)^2\implies A=225\pi \implies \boxed{A\approx 706.86}

6 0
2 years ago
Find the products (4m+5)(3m-6)
Vesnalui [34]

Answer:

12m^2 - 9m -30

Step-by-step explanation:

So rewrite the equation to this:

4m * 3m

4m * -6

5 * 3m

5 * -6

Now solve:

4m * 3m = 12m^2

4m * -6 = -24m

5 * 3m = 15m

5 * -6 = -30

Now add them together in order:

12m^2 - 24m + 15m - 30

Simplify -24m and 15m:

12m^2 - 9m -30

Thus

12m^2 - 9m -30 is the answer

Hope this helps!

4 0
3 years ago
Read 2 more answers
Find the difference. (9/x^2-9x)-(6/x^2-81)
Sunny_sXe [5.5K]

The difference is  $\frac{3 x+81}{x(x-9)(x+9)}$

Explanation:

The expression is $\left(\frac{9}{x^{2}-9 x}\right)-\left(\frac{6}{x^{2}-81}\right)$

Removing the parenthesis, we have,

$\left\frac{9}{x^{2}-9 x}\right-\left\frac{6}{x^{2}-81}\right$

Factoring the terms $x^{2}-9 x$ and $x^{2}-81$, we get,

$\frac{9}{x(x-9)}-\frac{6}{(x+9)(x-9)}$

Taking LCM, we get,

$\frac{9(x+9)-6x}{x(x-9)(x+9)}}$

Simplifying the numerator, we get,

$\frac{9x+81-6x}{x(x-9)(x+9)}}$

Subtracting the numerator, we have,

$\frac{3 x+81}{x(x-9)(x+9)}$

Hence, the difference is $\frac{3 x+81}{x(x-9)(x+9)}$

7 0
2 years ago
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