Can someone please answer this question 3[(x^2)^3]^0
1 answer:
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The number of solutions in each equation are as follows:
- 1 solution: 4^x = 2^{-x}
- 2 solution: 3/2x + 2 = 2^{x} + 1 and 3x + 1 = 2^{-x}.
- No solution: 4^x + 2 = 3^x - 1 and 2x - 5 = 3^{x} + 2.
In order to determine the number of solutions, we would split the single equation to two different equations and then plot a graph, so as to reveal their solutions.
This ultimately implies that, the number of solutions is equal to the point of intersection between the lines of the equations plotted on a graph.
In conclusion, the number of solutions in each equation are as follows:
- 1 solution: 4^x = 2^{-x}
- 2 solution: 3/2x + 2 = 2^{x} + 1 and 3x + 1 = 2^{-x}.
- No solution: 4^x + 2 = 3^x - 1 and 2x - 5 = 3^{x} + 2.
Read more on number of solutions here: brainly.com/question/12558210
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