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kotykmax [81]
3 years ago
12

Can you help me please help me

Mathematics
1 answer:
pashok25 [27]3 years ago
4 0

Answer:

I can`t really see the question that well, but if I understand correctly here`s the first few.

1. Subtraction

2. Addition

3. Addition

4. Subtraction

5. Addition

6. Subtraction

It looks like its asking what is happening in those situations (is the number being added or subtracted). Sorry if that`s not much help

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How does the graph of the function g(x) = 5x + 1 differ from the graph of f(x) = 5*?
elena-14-01-66 [18.8K]

Answer:

C. It is translated up 1 unit.

Step-by-step explanation:

Translations of a function f(x)

To translate a function f(x) a units to the right, we have f(x-a)

To translate a function f(x) a units to the left, we have f(x+a)

To translate a function f(x) a units up, we have f(x) + a

To translate a function f(x) a units down, we have f(x) - a

In this question:

g(x) = 5x + 1

f(x) = 5x

This means that the function g(x) is 1 added to the function f(x), that is, it is translated up 1 units, and the correct answer is given by option c.

7 0
3 years ago
A television weighs 60 kilograms. How many grams does it weigh?
Sever21 [200]
60 Kilograms equal 60000 Grams
5 0
3 years ago
Read 2 more answers
-6 = n/2 - 10 show work
valina [46]

Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

First, add 10 to both sides

-6 (+10) = n/2 - 10 (+10)

10 - 6 = n/2

4 = n/2

Next, isolate the n. Multiply 2 to both sides

4(2) = n/2(2)

n = 4(2)

n = 8

8 is your answer

hope this helps

5 0
4 years ago
how many gallons each of 25% alcohol and 5% alcohol should be mixed to ontain 20 gal of 24% alcohol?​
lisov135 [29]

Answer:

11/20 of 20 gallons

Step-by-step explanation:

3 0
3 years ago
use the quadratic formula to find the zeros of the function round to the tense of necessary y= 17x^2-21
Kitty [74]
y=17x^2-21\\\\\text{The zeros of the function:}\ y=0\iff17x^2-21=0\ \ \ |+21\\\\17x^2=21\ \ \ |:17\\\\x^2=\dfrac{21}{17}\to x=\pm\sqrt{\dfrax{21}{17}}\\\\x\approx-1.1\ \vee\ x\approx1.1

\text{Use the quadratic formula:}\\\\y=17x^2-21\\\\a=17;\ b=0;\ c=-21\\\\b^2-4ac=0^2-4\cdot17\cdot(-21)=1428\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-0-\sqrt{1428}}{2\cdot17}=-\dfrac{\sqrt{1428}}{34}\approx-1.1\\\\x_2=\dfrac{-0+\sqrt{1428}}{2\cdot17}=\dfrac{\sqrt{1428}}{34}\approx1.1
6 0
3 years ago
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