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kotykmax [81]
3 years ago
12

Can you help me please help me

Mathematics
1 answer:
pashok25 [27]3 years ago
4 0

Answer:

I can`t really see the question that well, but if I understand correctly here`s the first few.

1. Subtraction

2. Addition

3. Addition

4. Subtraction

5. Addition

6. Subtraction

It looks like its asking what is happening in those situations (is the number being added or subtracted). Sorry if that`s not much help

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Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0
3 years ago
What is the difference between discrete vs continuous data
Sergeeva-Olga [200]
With continuous data, it is possible to find the midpoint of any two distinct values. For instance, if h = height of tree, then its possible to find the middle height of h = 10 and h = 7 (which in this case is h = 8.5)

On the other hand, discrete data can't be treated the same way (eg: if n = number of people, then there is no midpoint between n = 3 and n = 4). 

-------------------------------------

With that in mind, we have the following answers

1) Continuous data. Time values are always continuous. Any two distinct time values can be averaged to find the midpoint

2) Continuous data. Like time values, temperatures can be averaged as well. 

3) Discrete data. Place locations in a race or competition are finite and we can't have midpoints. We can't have a midpoint between 9th and 10th place for instance.

4) Continuous data. We can find the midpoint and it makes sense to do so when it comes to speeds. 

5) Discrete data. This is a finite number and countable. We cannot have 20.5 freshman for instance.
4 0
3 years ago
5th grade math. correct answer will be marked brainliest
kipiarov [429]
The correct answer is 67 ur welcome
4 0
2 years ago
Read 2 more answers
URGENT 50 PTS
Len [333]
Point c

explanation:
6 0
2 years ago
2 to the fourth power subtracted by 8 multiplied by 2 divided by 4 simpified
Korvikt [17]

2^4-8x2/4  (PEMDAS) Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction

first you want to do exponents.. so 2x2x2x2 = 16

then you want to do multiplication so.. -8x2 = -16

now you have.. 16-16/4 .. then you want to do division so divide -16 by 4 and get -4

then you're left with 16-4 which is 12

THE ANSWER IS 12

6 0
3 years ago
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