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SSSSS [86.1K]
3 years ago
11

What is the solution to the system of equations below? y = negative one-third x + 9 and y = two-thirds x minus 12 (21, 2) (21, –

10) (–21, 16) (–21, –26)
Mathematics
1 answer:
lora16 [44]3 years ago
6 0

Answer:

(21, 2 )

Step-by-step explanation:

Given the 2 equations

y = - \frac{1}{3} x + 9 → (1)

y = \frac{2}{3} x - 12 → (2)

Substitute (2) into (1)

\frac{2}{3} x - 12 = - \frac{1}{3} x + 9 ( add \frac{1}{3} x to both sides )

x - 12 = 9 ( add 12 to both sides )

x = 21

Substitute x = 21 into either of the 2 equations and evaluate for y

Substituting into (2)

y = \frac{2}{3} × 21 - 12 = 14 - 12 = 2

Solution is (21, 2 )

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Please help thank you
Keith_Richards [23]

Answer:

5

alternates

Step-by-step explanation:

The series is for k = 0 to 4, so k = 0, 1, 2, 3, 4.

That is 5 terms.

-1/2 is inside the parentheses and is raised to 0, 1, 2, 3, 4.

A negative number raised to an even integer is positive.

A negative number raised to an odd integer is negative.

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7 0
3 years ago
Evaluate the numerical expression 4(8 - 2) = (-3) + 7
Fofino [41]

Answer:

4 ( 8 - 2 ) = (-3) + 7 -> this is a false statement

Step-by-step explanation:

4 ( 8 - 2 ) = ( -3 ) + 7

Simplify the parenthesis

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Multiply;

24 = (-3) + 7

Add, remember, adding a negative number and a positive number is the same as subtracting the negative number from the positive number,

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This statement is not true.

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3 years ago
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