Answer:
1) 0.1667
2) 0.8333
3) 1
Step-by-step explanation:
Let A be the event that 3 is observed on the first trial.
Let B be the event that at least two trials are required to observe a 3
a) A six-sided die has 6 possible outcomes of 1,2,3,4,5,6
3 is one of the six possible outcomes
P(A) = no of favourable outcomes /no of possible outcomes
P(A) = 1/6 = 0.1667
b) The event of requiring at least two trials to observe a 3 is the event of not observing a 3 on the first trial.
P(B) = P(A')
P(A')= 1 - P(A)
P(B) = 1 - 1/6
= 5/6 = 0.8333
c) P(AnB) = P(A) + P(B)
= 1/6 + 5/6
= 6/6 = 1
33 Pages.
103-13=90 dollars
90/3=30 pages
30 pages + 3=33
Answer:
x = 20
p =54
y= 54
Step-by-step explanation:
2x-4 = 96-3x
5x = 100
x = 20
2x-4 = 40-4 = 36
(180 - (36 x 2))/2
(180-72)/2
108/2
p = y =54
The answer is of course E -340
