Let p: a number is greater than 25 let q: a number is less than 35 if p q is true then what could the number be?
1 answer:
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The answer is 12 J.
The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):
The unit of the kinetic energy is Joules (J = kg · (m/s)²).
It is given:
m = 1.5 kg
v = 4 m/s
It is unknown:
KE = ?
Thus:
<span>
</span>
<span>
</span>
Therefore, the kinetic energy of the bird is 12J.
The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):
The unit of the kinetic energy is Joules (J = kg · (m/s)²).
It is given:
m = 1.5 kg
v = 4 m/s
It is unknown:
KE = ?
Thus:
<span>
<span>
Therefore, the kinetic energy of the bird is 12J.
Answer:
a) <em> standard error of the mean =10.06</em>
<em>b) The margin of error = 17.3982</em>
<em>c) 95% of confidence intervals are </em>
<em></em><em></em>
<em>d) Lower limit of 95% of confidence interval = 89.6018</em>
<em>upper limit of 95% of confidence interval = 124.3982</em>
<em>The Population mean is lies between in these intervals</em>
<u>Step-by-step explanation:</u>
<u><em>Step(i)</em></u><u>:-</u>
Given sample size 'n' = 20
Given sample mean was found to be 107 bpm with a standard deviation of 45 bpm.
<em>Sample mean </em><em></em>
<em>Sample standard deviation (S) = 45 bpm</em>
<em>a) standard error of the mean is determined by</em>
<em> </em><em></em>
<em> S.E = 10.06</em>
<em>b) The margin of error is determined by</em>
<em></em><em></em>
<em>The degrees of freedom ν </em><em></em>
<em> </em>
<em></em><em></em>
<em></em><em></em>
<em>c) 95% of confidence intervals are determined by</em>
<em></em><em></em>
<em></em><em></em>
<em></em><em></em>
<em></em><em></em>
<em>d) </em>
<em>Lower limit of 95% of confidence interval = 89.6018</em>
<em>upper limit of 95% of confidence interval = 124.3982</em>
<em>The Population mean is lies between in these intervals</em>
<em></em>
<em></em>