2x -20 -1 =0
2x -21=0
2x=21
x= 10.5
Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
Answer:
3
Step-by-step explanation:
A coefficient is a numerical factor that contains a variable.
In this case, 3 is a numerical factor and contains a variable (y).
Hence,
3 is the coefficient of the expression.
