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3 years ago

PLEASE HELP!!!! Geometry is so hard and this is due tonight :(

Mathematics

1 answer:

omeli [17]3 years ago

7 0

Cos(68)=z/24
Z=24cos(68)
Find the answer by the calculator

Second question,
Cos(x)=16/34
X=cos^-1(16/34)
Use calculator

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75% of ____ =48<br> Helppppp

Nataliya [291]

Answer:

Step-by-step explanation:

75% of 64 = 48

5 0

3 years ago

I need to make this expression true by using grouping symbols. 2x2+3^2 -4+3x5

Novay_Z [31]

Simply 3^2 to 9

2×2+9−4+3×5

Simplify 2 x 2 to 4

4+9−4+3×5

Simplify 3 x 5 to 15

4+9−4+15

Simplify

= 24

7 0

3 years ago

URGANT!!! find the coordinates of where the line 2x+3y=12

bezimeni [28]

This has infinitely many solutions if that is all that the question asked...

2x+3y=12

3y=-2x+12

y=(-2x+12)/3

So for any value of x you choose it will give you the corresponding y value that makes your original equation true.

4 0

3 years ago

Read 2 more answers

Please guys please pllease

klio [65]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

Let's calculate its discriminant :

$\qquad \sf \dashrightarrow \: 4 {u}^{2} + 16u + 41 = 40$

$\qquad \sf \dashrightarrow \: 4 {u}^{2} + 16u + 41 - 40 = 0$

$\qquad \sf \dashrightarrow \: 4 {u}^{2} + 16u + 1 = 0$

Here, if we equate it with general equation,

a = 4

b = 16

c = 1

$\qquad \sf \dashrightarrow \: disciminant = {b}^{2} - 4ac$

$\qquad \sf \dashrightarrow \: d = (16) {}^{2} - (4 \times 4 \times 1)$

$\qquad \sf \dashrightarrow \: d = (16) {}^{2} - (16)$

$\qquad \sf \dashrightarrow \: d = 16(16 - 1)$

$\qquad \sf \dashrightarrow \: d = 16(15)$

$\qquad \sf \dashrightarrow \: d = 240$

Now, since discriminant is positive ; it has two real roots ~

The roots are :

$\qquad \sf \dashrightarrow \: u = \dfrac{ - b \pm \sqrt{ d } }{2a}$

$\qquad \sf \dashrightarrow \: u = \dfrac{ - 16\pm \sqrt{ 240 } }{2 \times 4}$

$\qquad \sf \dashrightarrow \: u = \dfrac{ - 16\pm 4\sqrt{ 15 } }{8}$

$\qquad \sf \dashrightarrow \: u = \dfrac{ 4(- 4\pm \sqrt{ 15 }) }{8}$

$\qquad \sf \dashrightarrow \: u = \dfrac{ - 4\pm \sqrt{ 15 } }{2}$

So, the required roots are :

$\qquad \sf \dashrightarrow \: u = \dfrac{ - 4 - \sqrt{ 15 } }{2} \: \: and \: \: \dfrac{ - 4 + \sqrt{15} }{2}$

4 0

2 years ago

Read 2 more answers

Simplify:<br> 9x² - 4x - 3= [?]<br> X=-2

Bess [88]

Answer:

Step-by-step explanation:

Given x = -2,

Substitute x into the expression. $9x^{2} -4x-3=9(-2)^{2} -4(-2)-3\\= 9(4)-4(-2)-3\\= 36+8-3\\=44-3\\=41$

4 0

1 year ago