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vlada-n [284]
3 years ago
15

Sixty percent of eighth graders at the new middle school ride a bus to school.If 228 8th graders ride the bus to school,how many

eighth graders are in the school?

Mathematics
2 answers:
qaws [65]3 years ago
7 0
136.8 eighth graders
natka813 [3]3 years ago
7 0
That is the way I learned it

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Find x (Will mark brainliest if you are right)
Marizza181 [45]

Answer:

Step-by-step explanation:

(-3x + 2)(45x + 21) + (-4x + 25) = 50

-135x^2 - 63x + 90x + 42 - 4x + 25 = 50

-135x^2 + 23x + 67 = 50

-135x^2 + 23x + 67 - 50 = 0

-135x^2 + 23x + 17 = 0

quadratic formula : x = (-b ± √b^2 - 4ac)/2a

a = -135, b = 23, c = 17

x = -23 ± √23^2 - 4(-135)(17) / (2(-135)

x = (-23 ±√9709 )/ -270

x = 23/270 ± 1 / 270√9709/270

x = 0.4501 or x = - 0.2798 <=== these answers are rounded

4 0
3 years ago
Please please help me with this question please now and show your steps
sattari [20]

Answer:

y =  {x}^{2}  - 8x + 7 \\ a = 1 \: and \: b = -  8 \\ the \: line \: of \: symmetry \:  \\ x =  \frac{ - b}{2a}  =  \frac{8}{2}   \\ x = 4(line \: of \: symmetry) \\ y =  {4}^{2}  - 8(4) + 7  \\ = 16 + 32 + 7 = y = 55 \\ vertix \: is \: (4  ,55) \\ y =  {0}^{2}  - 8(0) + 7 \\ y = 7 \\ 0 =  {x}^{2}  - 8x + 7 \\ (x - 7)(x - 1) = 0

6 0
2 years ago
What is the slope of the line with equationy-3=-x-2)?<br> 3)<br> (42).
gulaghasi [49]

Answer:

Step-by-step explanation:

-3 = -x - 2

the equation is a bit hard to read in your questions but if that is the correct equation then the slope is  -1

4 0
2 years ago
A computer can be classified as either cutting dash edge or ancient. Suppose that 94​% of computers are classified as ancient. ​
taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94​% of computers are classified as ancient.

(a) <u>Two computers are chosen at random.</u>

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 2 computers

            r = number of success = both 2

           p = probability of success which in our question is % of computers

                  that are classified as ancient, i.e; 0.94

<em>LET X = Number of computers that are classified as ancient​</em>

So, it means X ~ Binom(n=2, p=0.94)

Now, Probability that both computers are ancient is given by = P(X = 2)

       P(X = 2)  = \binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}

                      = 1 \times 0.94^{2} \times 1

                      = 0.8836

(b) <u>Eight computers are chosen at random.</u>

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 8 computers

            r = number of success = all 8

           p = probability of success which in our question is % of computers

                  that are classified as ancient, i.e; 0.94

<em>LET X = Number of computers that are classified as ancient</em>

So, it means X ~ Binom(n=8, p=0.94)

Now, Probability that all eight computers are ancient is given by = P(X = 8)

       P(X = 8)  = \binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}

                      = 1 \times 0.94^{8} \times 1

                      = 0.6096

(c) <u>Here, also 8 computers are chosen at random.</u>

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 8 computers

            r = number of success = at least one

           p = probability of success which is now the % of computers

                  that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

<em>LET X = Number of computers classified as cutting dash edge</em>

So, it means X ~ Binom(n=8, p=0.06)

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X \geq 1)

       P(X \geq 1)  = 1 - P(X = 0)

                      =  1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}

                      = 1 - [1 \times 1 \times 0.94^{8}]

                      = 1 - 0.94^{8} = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge​ is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0
2 years ago
1) Which diagram shows the correct construction of a line parallel to line l and passing through point P?
kherson [118]

1)To construct a line parallel to line l and passing through point P our first step is to join the point and line and then draw angles in such a way so that corresponding angles are equal.

Option B is the correct construction of a line parallel to line l and passing through point P.

2) To Construct the perpendicular line to line DE at point F we cut an arc from point F  to line DE in such a way it cuts line DE at two points .From these two points we draw arcs which cut each other .

Option C is the correct option  to Construct the perpendicular line to line DE at point F.

3) To Construct a perpendicular from the given line segment that passes through the given point we cut two arcs on top and bottom of line segment.

Option B is the right answer.

3 0
3 years ago
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