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nirvana33 [79]
3 years ago
12

Angle MNO is rotated 90 degrees counterclockwise about the origin to form angle M'N'O'. Which statement shows the measure of ang

le M'N'O'?
m∠ M'N'O' = 90 degrees
m∠ M'N'O'= 180 degrees
m∠ M'N'O' = 2 ⋅ m∠MNO
m∠ M'N'O' = m∠MNO

Mathematics
2 answers:
vodomira [7]3 years ago
8 0
<span>The answer is "m∠ M'N'O' = m∠MNO"</span>
Jobisdone [24]3 years ago
6 0

Answer:

The answer is m∠ M'N'O' = m∠MNO

Step-by-step explanation:

If the Angle MNO is rotated 90 degrees counterclockwise about the origin. The new angle formed by ' will be the same as the rotation doesn't alter neither the shape or size of the figure. Therefore, we can conclude that MNO and M'N'O' are congruent (Same lenght and angle).

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Answer:

formula: 2πrh

Step-by-step explanation:

2πrh= 2×π×4×5≈125.66371

3 0
3 years ago
Which expression is equivalent ?<br><br> LOOK AT THE PICTURE
victus00 [196]

Answer:

x^ (5/3) y ^ 1/3

Step-by-step explanation:

Rewriting as exponents

(x^5y) ^ 1/3

We know that a^ b^c = a^(b*c)

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8 0
4 years ago
Read 2 more answers
Simplify the expression. (16y54y3)12 Enter your answer in the box.
sp2606 [1]

Answer:

Simplify the expression: (16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}

Use the exponent power:

  • a^n \cdot a^m = a^{n+m}
  • \sqrt[n]{a^n} =a
  • (a^n)^m = a^{nm}

(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}

Apply the given rules;

(16y^{\frac{5}{4} +3} )^{\frac{1}{2}}

Simplify:

(16y^{\frac{17}{4}} )^{\frac{1}{2}}

then;

(16)^{\frac{1}{2}} \cdot (y^{\frac{17}{4}})^{\frac{1}{2}} = 4y^{\frac{17}{8}}

Therefore, the simplified expression of (16y^{\frac{5}{4}}y^3)^{\frac{1}{2}} is, 4y^{\frac{17}{8}}


7 0
3 years ago
What value of k will result in the quadratic having one rational solution if 4x2+kx+4=0?
PtichkaEL [24]

The value of 'k' in the quadratic Equation    4x^{2}+kx+4=0 having one rational solution is k is 8.

<h3>What is a Quadratic Equation?</h3>
  • Quadratic equations are the polynomial equations of degree 2 in one variable of the type f(x) = ax^{2} + bx + c = 0 where a, b, c, ∈ R and a ≠ 0.
  • The standard form of a quadratic equation is ax^{2} + bx + c = 0 .

Here, the given equation is  4x^{2}+kx+4=0

By comparing the given equation with the standard form of the quadratic equation we get,

a = 4

b = k

c = 4

The given quadratic is having one rational solution, which means b^{2} -4ac=0

Therefore,

k^{2} -4 \times 4\times4=0\\k^{2} -64=0\\k^{2} =64\\k=\sqrt{64} \\k=8

Therefore, the value of k is 8.

Learn more about the quadratic equation is brainly.com/question/8649555

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7 0
2 years ago
4+ a/5= 8<br> What is the solution to the equation?
den301095 [7]
A= 20 let me know if you need an explanation❤️, mark me branliest pls
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3 years ago
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