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3 years ago

Complete the table for y=1/2x+3

Mathematics

1 answer:

andrew-mc [135]3 years ago

6 0

X 0 2 4 -2 -4
y 3 4 5 2 1

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igor_vitrenko [27]

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Step-by-step explanation:

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3 years ago

Arturiano [62]

Answer: C

Step-by-step explanation:

We know the scale factor is 6/2=3.

A) False. The ratio of the side lengths, not the areas, is 1 to 3.

B) False. Rectangle B is larger than Rectangle A.

C) The square of the ratio of the side lengths is the ratio of the areas.

D) False. The ratio of the side lengths, not the areas, is 1 to 3.

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2 years ago

Find the Value of 2a2+5b2

Valentin [98]

Answer:

I get 92 but not really sire

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3 years ago

Write two inequalities to compare 39 and -39

Igoryamba

39 >-39 , |39| = |-39| there you go

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3 years ago

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

$AB = \sqrt{49}$

$\sqrt{49} =7$

AB = 7 units

As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

$BC = \sqrt{36}$

$\sqrt{36} =6$

BC = 6 units

As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0

3 years ago

Read 2 more answers