Answer:
<h2>A</h2>Step-by-step explanation:
y > 0 - the region above the line together with that line
y ≥ 0 - the region above the line together with that line
y < 0 - the region below the line without that line
y ≤ 0 - the region below the line together with that line
We have:
y > 2 - the region above the line together with that line
y ≥ 2x - 3 - the region above the line together with that line
<em>look at the picture</em>
The common part is the solution.
Answer:
An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:
Step-by-step explanation:
We know that the slope-intercept form of the line equation is
y=mx+b
where m is the slope and b is the y-intercept.
Given the line
6x+y=2
Simplifying the equation to write into the slope-intercept form
y = -6x+2
So, the slope = -6
As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.
Thus, the slope of the perpendicular line will be: -1/-6 = 1/6
Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be
substituting the values m = 1/6 and the point (6, -2)
subtract 2 from both sides
Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:
