Which choicest are equivalent to the fraction below check all that apply 12/32

Elise and her dad are planning to attend the state fair. An adult ticket is $21.00. The price of an adult ticket is $10.00 more

sashaice [31]

Answer:The equation to determine how much Elise will pay for a student ticket is 2x = 33

Step-by-step explanation:

Let x represent the price of one student ticket.

Elise and her dad are planning to attend the state fair and the price of an adult ticket is $21.00

The price of an adult ticket is $10.00 more than two thirds the price of a student ticket. This means that

21 = 2/3 × x + 10

The equation to determine how much Elise will pay for a student ticket would be

2x/3 + 10 = 21

2x/3 = 21 - 10 = 11

2x = 11×3 = 33

x = 33/2 = $16.5

5 0

3 years ago

How much less would a 23-year-old female pay for a $25,000 policy of 20 year life insurance (@ $2.90 per $1000) than straight li

mojhsa [17]

Answer:

The female would pay $322.00 less for a policy of $25,000

Step-by-step explanation:

Since we have given that

Amount for policy = $25000

If she opt for 20 year life insurance at $2.90 per $1000.

so, her amount of premium becomes

$25000\times \frac{2.9}{1000}$

=$72.50

If she opt for straight life insurance at $15.78 per $1000,

Then, her amount of premium becomes

$25000 \times \frac{15.78}{1000}$

= $394.50

Difference between them is given by

$394.50-$72.5 = $322.00

5 0

4 years ago

Read 2 more answers

Anwers : a. dotted b. y=-x+4 c. y=x-4 d. y=x+1 e. solid f. yes g. no

Ksenya-84 [330]

Answer:

Those answers are correct

5 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

The sum of three consecutive even numbers is 582. What is the 1st number?

Snezhnost [94]

Answer:

d

Step-by-step explanation:

y

4 0

3 years ago