Which choicest are equivalent to the fraction below check all that apply 12/32

Anyone please help me with this question.

Ierofanga [76]

Answer:

The answer is 207 miles per hour

Step-by-step explanation: You can find this answer by taking 332 and converting it to a fraction and then multiplying it by 5/8. That would look like this 332/1 X 5/8 = x. Then you multiply then numerators, then denominators and simplify the fraction. Next you can divide the numerator by the denominator. And once you have this you round to the nearest whole number.

Hope this helps.

5 0

3 years ago

Read 2 more answers

From a thin piece of cardboard 50 in. by 50 in., square corners are cut out so that the sides can be folded up to make a box. Wh

mixer [17]

Answer:

When dimension of box is 33.33 inches × 33.33 inches ×8.33 then its volume is maximum and is 9259.26 cubic inches.

Step-by-step explanation:

Let h be the length (in inches) of the square corners that has been cut out from the cardboard and that would be the height of the cardboard box.

Since the squares have been cut from cardboard, both sides of the cardboard would reduce by 2h.

Thus, The dimension of box is (50 – 2h) × (50 – 2h) × h in dimensions.

The volume V of rectangular box = (Length × Breadth × Height) cubic inches.

$V=(50-2h) \times (50-2h) \times h$

$V=(50-2h)^2 \times h$ ..............(1)

Using $(a-b)^2=a^2+b^2-2ab$

$V=h(2500+4h^2-200h)$

$V=2500h+4h^3-200h^2$

For obtaining a box of maximum volume, maximize V as a function of h.

Differentiate both sides with respect to h,

$\frac{dV}{dh}=2500+12h^2-400h$

$\frac{dV}{dh}=4(625+3h^2-100h)$

Solving quadratic equation, $625+3h^2-100h$

$\frac{dV}{dh}=4(3h^2-25h-75h+625)$

$\frac{dV}{dh}=4(h(3h-25)-25(3h-25))$

$\frac{dV}{dh}=4((h-25)(3h-25))$

For maximum, $\frac{dV}{dh}=0$

thus, $4((h-25)(3h-25))=0$

⇒ $h= 25$ or $h=\frac{25}{3}$

Now check (1) for $h= 25$ and $h=\frac{25}{3}$ .

$h= 25$ is not possible as when h is 25 inches then length and breadth becomes 0.

When $h=\frac{25}{3}$ .

(1) ⇒ $V=(50-2(\frac{25}{3}))^2 \times\frac{25}{3}=9259.2592593$

This is the maximum volume the box can assume.

Thus, when dimension of box is 33.3 inches × 33.3 inches ×8.3 then its volume is maximum and is 9259.26 cubic inches.

6 0

3 years ago

Can some help me with this please.

MrMuchimi

Zane was -25 meters from the edge of the volcano when he started:)

3 0

3 years ago

1.

Ivenika [448]

Answer:

Step-by-step explanation:

hello :

an equation of the circle Center at the A(a,b) and ridus : r is :

(x-a)² +(y-b)² = r²

..... ( standard form )

x²+y²+10x-4y-12=0

(x² +10x) + (y²- 4y) -12 = 0

(x² +2(5)(x) +5² -5²) + ( y² -2(2)(y) +2² -2²) -12 = 0

(x + 5)² - 25 + ( y - 2 )² - 4 -12 = 0

(x + 5 )² + ( y - 2 )² = 41 ..... ( standard form )

the center is the point A(-5 ; 2) and ridus r = √41

7 0

4 years ago

patricia says that it's more appropriate to use the method of factoring than extracting square roots in solving 4x2^-9=0. do you

zavuch27 [327]

$1^{o} \\ \\ 4x^{2}-9=0 \\ \\ (2x-3)(2x+3)=0 \\ \\ 2x-3=0 \ \vee \ 2x+3=0 \\ \\ 2x=3 \ \vee \ 2x=-3 \\ \\ x= \frac{3}{2} \ \vee \ x=- \frac{3}{2} \\ \\ 2^{o} \\ \\ 4x^{2}-9=0 \\ \\ 4x^{2}=9 \\ \\ x^{2}= \frac{9}{4} \\ \\ x= \sqrt{ \frac{9}{4} } \ \vee \ -\sqrt{ \frac{9}{4} } \\ \\ x= \frac{3}{2} \ \vee \ x=- \frac{3}{2} \\ \\ 3^{o} \\ \\ 4x^{2}-9=0 \\ \\ \Delta=0^{2}-4*4*(-9)=144 \\ \\ \sqrt{\Delta} =12 \\ \\ x_{1}= \frac{0+12}{8} = \frac{3}{2}$

$x_{2}= \frac{0-12}{8} =- \frac{3}{2}$

8 0

4 years ago