Answer:
brainliest plzzz
Step-by-step explanation:
y = 2x
Let x = 1.5
y = 2*1.5
y = 3
Let x= 4
y = 2*4
y = 8
So to get the answer you do 100100100+303030-101010 which = 100302120 x 10 (the amount she/he gets for each subscriber) which is the amount of money Kiersten earned.
Hope this helped
Answer:
you spent all together 40.2+24.5+37.8=$102.50.
you saved 19.8+10.5+7.2=$37.50
![\frac{102.50}{140}](https://tex.z-dn.net/?f=%5Cfrac%7B102.50%7D%7B140%7D)
Step-by-step explanation:
To find the amount we spend, we multiply the original price by the decimal conversion of each fraction. Then we add the amounts together.
Sneakers cost $60 and you bought them at 2/3=0.6666....
60(0.67)=$40.20 and saved $19.80
Sweater costs $35 and you bought it at 7/10=0.7
35(0.7)=$24.50 and saved $10.50
A jacket costs $45 and you bought it at 5/6=0.8333...
45(0.84)=$37.80 and saved $7.20
We spent all together 40.2+24.5+37.8=$102.50.
We saved 19.8+10.5+7.2=$37.50
We could of spent paying regular price 60+35+45=$140. To find the fraction we place the total we actually paid over the total regular price.
Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.
Step-by-step explanation:
The equation of a circle in the center-radius form is:
(1)
Where
are the coordinates of the center and
is the radius.
Now, we are given the equation of this circle as follows:
(2)
And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:
(3)
Rearranging the equation:
(4)
(5)
Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of
:
<u>For the first parenthesis:</u>
![x^{2}+6x+b^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%2B6x%2Bb%5E%7B2%7D)
We can rewrite this as:
![x^{2}+2(3)x+b^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%2B2%283%29x%2Bb%5E%7B2%7D)
Hence in this case
and
:
![x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%2B2%283%29x%2B3%5E%7B2%7D%3Dx%5E%7B2%7D%2B6x%2B9%3D%28x%2B3%29%5E%7B2%7D)
<u>For the second parenthesis:</u>
![y^{2}-8y+b^{2}](https://tex.z-dn.net/?f=y%5E%7B2%7D-8y%2Bb%5E%7B2%7D)
We can rewrite this as:
![y^{2}-2(4)y+b^{2}](https://tex.z-dn.net/?f=y%5E%7B2%7D-2%284%29y%2Bb%5E%7B2%7D)
Hence in this case
and
:
![y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}](https://tex.z-dn.net/?f=y%5E%7B2%7D-2%284%29y%2B4%5E%7B2%7D%3Dy%5E%7B2%7D-8y%2B16%3D%28y-4%29%5E%7B2%7D)
Then, equation (5) is rewritten as follows:
(6)
<u>Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.</u>
Rearranging:
(7)
At this point we have the circle equation in the center radius form ![(x-h)^{2} +(y-k)^{2}=r^{2}](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%20%2B%28y-k%29%5E%7B2%7D%3Dr%5E%7B2%7D)
Hence:
![h=-3](https://tex.z-dn.net/?f=h%3D-3)
![k=4](https://tex.z-dn.net/?f=k%3D4)
![r=\sqrt{100}=10](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B100%7D%3D10)