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ElenaW [278]
3 years ago
9

Consider two events such that P(A) = 1/4 , P(B) = 2/3 , and P(A ∩ B) = 1/5 . Are events A and B independent events?

Mathematics
1 answer:
fredd [130]3 years ago
4 0
P(A) = 1/4
p(B) = 2/3
p(A ∩ B) = 1/5
p(A).p(B) = 2/12 = 1/6 ≠p(A ∩ B )
thus no, they are dependent because P(A) ⋅ P(B) ≠ P(A ∩ B)
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Round this number to the nearest tenth 4.9675
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.. 4.9675 +0.05 = 5.0175
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How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
konstantin123 [22]

440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440

Thus 440 gallons of 80 % antifreeze solution must be mixed

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2 years ago
Anne bought 6 cans of paint and 2/3 of a pint of special paint additive formulated to reduce
iogann1982 [59]

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Step-by-step explanation:

[Given] 2/3 / 6

["Keep, change, flip"] 2/3 * 1/6

[Multiply] 2/18

[Simplify] 1/9

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0
2 years ago
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