Question

Nina purchased apples and strawberries. She purchased a total of 9 pounds of fruit and spent a total of $16.35. Strawberries cost $1.60 per pound and apples cost $ 1.99 per pound. How many pounds of each type of fruit did she buy?

Answer 1

Answer:

4 pounds of strawberries and 5 pounds of apples are bought.

Step-by-step explanation:

Given:

Total number of pounds of fruit = 9 pounds

Total money spent = $16.35

Cost of 1 pound of strawberry = $1.60

Cost of 1 pound of apple = $1.99

Let 'x' pounds of strawberries and 'y' pounds of apples are bought.

So, as per question:

The sum of the pounds is 9. So,

$x+y=9\\\\y=9-x----1$

Now, total sum of the fruits is equal to the sum of 'x' pounds of strawberries and 'y' pounds of apples. So,

$1.60x+1.99y=16.35----2$

Now, plug in the 'y' value from equation (1) in to equation (2). This gives,

$1.60x+1.99(9-x)=16.35\\\\1.60x+17.91-1.99x=16.35\\\\Combining\ like\ terms, we get:\\\\1.60x-1.99x=16.35-17.91\\\\-0.39x=-1.56\\\\x=\frac{-1.56}{-0.39}=4\ pounds$

Now, from equation 1, we have:

$y=9-4=5\ pounds$

Therefore, 4 pounds of strawberries and 5 pounds of apples are bought.