Answer:
It is expected that linearization beyond age 20 will be use a function whose slope is monotonously decreasing.
Step-by-step explanation:
The linearization of the data by first order polynomials may be reasonable for the set of values of age between ages from 5 to 15 years, but it is inadequate beyond, since the fourth point, located at 
, in growing at a lower slope. It is expected that function will be monotonously decreasing and we need to use models alternative to first order polynomials as either second order polynomic models or exponential models.
Step-by-step explanation:
5×6'3n=20
30'3n=20
3n=20-30
3n/3= -10/3
n= -3
The answer is C.
You want:
10 < a < 14 (greater or equal)
The difference between 10 and 12 is 2.
The difference between 12 and 14 is 2.
Therefore the absolute value allows you to express that the difference between a and 12 cannot be greater than 2 (either going up to a max of 14 or going down to a minimum of 10).
Answer: x=20
Step-by-step explanation:
63-x=2x+3
-x-2x+63=3
-x-2x=3-63
-3x=3-63
-3x=-60
-3x/3=-60/3
X=20
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Given
81 red balls
Number of balls per row = Number of rows
Procedure
b = Number of balls
r = Number of rows
T = Total number of balls
b = r
![\begin{gathered} T=b\cdot r \\ Given\text{ b=r} \\ T=b^2 \\ b=\sqrt[]{T} \\ b=\sqrt[]{81} \\ b=9 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20T%3Db%5Ccdot%20r%20%5C%5C%20Given%5Ctext%7B%20b%3Dr%7D%20%5C%5C%20T%3Db%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7BT%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B81%7D%20%5C%5C%20b%3D9%20%5Cend%7Bgathered%7D)
The answer is:
Number of rows = 9
Number of balls = 9
