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3 years ago

Thevalley was at least 4 feet below sea level Inequality? PLEASE HELP DUE TODAY!!!!

Mathematics

1 answer:

alukav5142 [94]3 years ago

7 0

X less than or equal to -4

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What is the probability of flipping exactly 6 heads when you flip 6 coins? Please explain your answer and those who waste an ans

kolbaska11 [484]

Binomial probability states that the probability of x successes on n repeated trials in an experiment which has two possible outcomes can be obtained by

(nCx).(p^x)⋅((1−p)^(n−x))

Where success on an individual trial is represented by p.

In the given question, obtaining heads in a trial is the success whose probability is 1/2.

Probability of 6 heads with 6 trials = (6C6).((1/2)^6).((1/2)^(6–6))

= 1/(2^6)

= 1/64

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3 years ago

Round 23,421 to the nearest thousand and ten thousand

Ronch [10]

To the nearest thousand is 23,000 and the nearest ten thousand is 20,000

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3 years ago

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Mrs. Sanchez is given a $550 hiring bonus with a new job. She earns an average commission of $275 per week for the year. If $68

Goshia [24]

She would get $11,314 for the year.

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3 years ago

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Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

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4 years ago

Collect like terms/equations

Vlad [161]

1. -3x and -6x
2. 21 and -13
3. 21 and -13
4. -10b and 6b, 15 and -5
5. -20 and 30, 4c and -2c

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3 years ago

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