Five exterior angles of a hexagon are 41° 32°,67º 71°, and 55°, What is the measure of the sixth exterior
angle?
Can yo help me w this pls
Answer:
Option A: P ≈ 38.7 in, A ≈ 63.7 in²
Step-by-step explanation:
We are told that △MNO ~△DEF. This means that they are similar triangles.
We can solve for this using scale factor.
a) Perimeter of △MNO
The scale factor of two similar triangles is equal to the ratio of the perimeter of the triangles
Scale factor(k) = ratio of the sides of the triangles
In the diagram we are given
Side of △MNO = 6.7in
Side of △DEF = 9in
Perimeter of △MNO = X
Perimeter of △DEF = 52in
Scale factor (k) = 6.7/9
Hence,
6.7/ 9 = X/52
Cross Multiply
9X = 6.7 × 52
X = 6.7 × 52/9
X = 38.711111111 inches
To the nearest tenth, Perimeter of △MNO = 38.7 inches
b) Area of △MNO
The square of the scale factor of two similar triangles is equal to the ratio of area of the triangles
Scale factor(k) = ratio of the sides of the triangles
In the diagram we are given
Side of △MNO = 6.7in
Side of △DEF = 9in
Area of △MNO = Y
Area of △DEF = 115in²
Scale factor (k) = 6.7/9
Hence,
(6.7/ 9)² = Y/115
6.7²/9² = Y / 115
Cross Multiply
9² × Y = 6.7² × 115
Y = 6.7²× 115 /9²
Y = 63.732716049 square inches
To the nearest tenth, Area of △MNO = 63.7 in²
Answer:
Step-by-step explanation:
Mr. Schwartz begins with total number of wheels = 85
he has to order more wheels once he left with less than 40 wheels
so min. no. of wheels he can use before ordering more wheels = 85-40 = 45
Mr. Schwartz uses 4 wheels to build 1 car
Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars
then, if he builds 12 cars then he needs 12×4 = 48 wheels
total supply of wheels he begins with = 85
wheels he used to build 12 cars = 48
so total number of wheels remaining are = 85-48 = 37
since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.
Answer:
um I not good at this but try to 2x with 5x than 4 and 2
