First you have to find the slope by subtracting y2 in this case (2) from y1 (8) dividing it over the subtraction of x2 (-8) and x1 (4) then once you get that you pick a point whether it’s (4,8) or (-8,2), plot it using the slope given to you and you’re done.
Answer:
As x approaches negative infinity, p(x) approaches positive infinity and q(x) approaches negative infinity.
Step-by-step explanation:
The order of the polynomial and the sign of the leading coefficient will let us find the correct answer easily,
If you get a negative number (such as negative infinity) and you take it to an odd power, (for example 3), you will still get a negative number.
As q(x) has a positive leading coefficient, this means that as x approaches negative infinity, q(x) will approach too negative infinity.
Since p(x) has an odd degree, but negative leading coefficient,
(-)*(-) = +
And this means that p(x) approaches positive infinity
Woah that looks hard and if no one answers just search it up
100,000,000 people would be the correct answer
