Ask question

Ask question

All categories

3 years ago

6

Find the volume of a cylinder with a radius of 5 cm and a height of 10 cm. Then, find the volume of the cylinder if the radius i

s increased to 10 cm. Leave your answers in term of pi.

2 answers:

Pepsi [2]3 years ago

8 0

Well pi times radius squared so 25* 3.14=78.5 * height so 78.5*10=785 is the answer for the first one so for the second take pi times radius squared so 100*3.14=314*10 = 3,140
1st answer 785cm squared
2nd answer 3,140cm squared

kap26 [50]3 years ago

3 0

Answer:

250π

1000π

Step-by-step explanation:

(refer to attached)

volume of cylinder is given by:

V = π r²h,

where r = radius of base and h = height of cylinder

Given r = 5 and h = 10, hence

V = π r²h

V = π (5)²(10)

V = π (25) (10)

V = 250π (answer)

For the second case, r = 10 cm

V = π r²h

V = π (10)²(10)

V = π (100) (10)

V = 1000π (answer)

You might be interested in

I neee help plss i have so lil time to hand it in

SashulF [63]

The Solution.

The given equation is

$\begin{gathered} y=|x|+7 \\ \text{Where x=11} \end{gathered}$

Substituting 11 for x, we can get the value of y.

$\begin{gathered} y=|11|+7 \\ y=11+7 \\ y=18 \end{gathered}$

Hence, the value of y is 18.

5 0

1 year ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

A sugar box manufacturing company is accurately making 100 g packets. Suppose a business researcher randomly selects 100 boxes,

creativ13 [48]

Answer:

...........................................................................

6 0

3 years ago

Brainliest to correct!

Nimfa-mama [501]

szaeAnswer:

fhx

Step-by-step explanation:ees

ffwsc

4 0

3 years ago

Read 2 more answers

Freee pointsss iggg :)

OlgaM077 [116]

Yayyy thanks a lottt can i also get brainliest

8 0

3 years ago

Read 2 more answers