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BabaBlast [244]
4 years ago
8

Which table represents exponential growth? A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. T

he second column is labeled y with entries 2, 4, 6, 8. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled y with entries 2, 4, 8, 16. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled y with entries 2, 4, 7, 11. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled y with entries 2, 4, 6, 10.
Mathematics
2 answers:
Papessa [141]4 years ago
8 0

Answer:

Table 2

Step-by-step explanation:

We have the tables:

<u>Table 1:</u>

x: 1  2  3  4

y: 2  4  6  8

<u>Table 2:</u>

x: 1  2  3  4

y: 2  4  8  16

<u>Table 3:</u>

x: 1  2  3  4

y: 2  4  7  11

<u>Table 4:</u>

x: 1  2  3  4

y: 2  4  6  10

An exponential growth data set will show a common ratio between y values. Let's look at each of the ratios from each table.

<u>Table 1:</u>

8/6 = 4/3

6/4 = 3/2

Already, we can see that 4/3 ≠ 3/2, which means that this doesn't have a common ratio. So Table 1 is wrong.

<u>Table 2:</u>

16/8 = 2

8/4 = 2

4/2 = 2

The common ratio here is 2, so we know this is correct.

<u>Table 3:</u>

11/7 = 1.57

7/4 = 1.75

Again, we can see that 1/57 ≠ 1.75, so this is wrong.

<u>Table 4:</u>

10/6 = 1.67

6/4 = 1.5

Again, there is no common ratio here, so this is wrong.

The answer is thus Table 2.

maks197457 [2]4 years ago
7 0

Answer:

Second table

The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled y with entries 2, 4, 8, 16

Step-by-step explanation:

y = 2^x

2 = 2¹

4 = 2²

8 = 2³

16 = 2⁴

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Answer:

69.14% probability that the diameter of a selected bearing is greater than 84 millimeters

Step-by-step explanation:

According to the Question,

Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.

  • In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ

we have μ=87 , σ=6 & X=84

  • Find the probability that the diameter of a selected bearing is greater than 84 millimeters

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