Let's use K for Kona and F for Fuji. The system of equations has to be a balanced system. For example, you can't mix the number of pounds of beans with the cost for each because pounds and dollars are different and you can only combine like terms...pounds with pounds and dollars with dollars. So let's start with the number of pounds. Since we don't know how much of each he bought we have the 2 unknowns, F and K, but we DO know that he bought 23 pounds total. So the first equation is
K + F = 23
Now let's see what we can do with the dollars. Again, we don't know how much he bought of each kind of coffee, but we do know that Kona beans cost $11 per pound and that Fuji beans cost $7.50 per pound, and we know that he spent a total of $197. So let's set that up:
11K + 7.50F = 197
Those are your 2 equations. It doesn't say you need to solve them, so you're done.
The x value in the second equation (y+2) is substituted for the x in the first equation in...
Answer A.
Answer:
x>6
Step-by-step explanation:
If the circle was filled in then it would have been ≥.
N = the number
9/10n + 6 = 51 Original Problem.
9/10n = 46 Subtract 6 from each side.
n = 51.11111111111111111111 Multiply each side by (10/9)
Answer: n = 51.111111111111111111111
Answer:
The number of
Dimes = d = 20 dimes
Quarters = q = 10 quarters
Step-by-step explanation:
Let us represent
The number of :
Dimes = d
Quarters = q
Note that:
A dime is worth 10 cents = 0.10d
A quarter is worth 25 cents = 0.25q
A Wonsan has 30 coins in her pocket, all of which are dimes and quarters .
d + q = 30...... Equation 1
d = 30 - q
If the total value of the coins is $4.50
0.10d + 0.25 q = 4.50.....Equation 2
We substitute 30 - q for d in Equation 2
0.10(30 - q) + 0.25q = 4.50
3 - 0.10q + 0.25q = 4.50
- 0.10q + 0.25q = 4.50 - 3
0.15q = 1.5
q = 1.5/0.15
q = 10 quarters
Solving for d
d = 30 - q
d = 30 - 10
d = 20 dimes
Therefore:
The number of
Dimes = d = 20 dimes
Quarters = q = 10 quarters