Actually the correct answer would be letter D. 89.7 mark as brainliest thanks
Remember the chain rule.
L(x)=f(g(x))
L'(x)=f'(g(x))g'(x)
take the derivative of f(g(x)). just treat them like they are variables. so you get:
h'=f'(g(x))g'(x)
now plug in your x value and evaluate:
h'(1)=f'(g(1))(g'(1))
substitute in values that you know and evaluate again
h'(1)=f'(3)(-3)
h'(1)=(-5)(-3)=15
Answer:
Step-by-step explanation: vcdvv
Answer:
look at the explanation
Step-by-step explanation:
in order to create a f(-2) you would need to know either a table of values or an equation to plug values into . . .saying a function of -2 does not really help, sorry
Cylinder has both circles top and bottom.