Ask question

Ask question

All categories

skelet666 [1.2K]

3 years ago

10

16 17 18 number plz answer righg

1 answer:

marta [7]3 years ago

7 0

What does this even mean

You might be interested in

Can someone help thank you

mestny [16]

Answer:

number 3 is a function, the other one is not a function.

the range for number 2 is -2,0,2,4 and for number 3 the rage is 0,1,2,3

8 0

3 years ago

Sean tossed a coin off a bridge into the stream below. The path of the coin can be represented by the equation 2 h tt = − 16t^2+

tekilochka [14]

Answer:

It will take 5.61 seconds for the coin to reach the stream.

Step-by-step explanation:

The height of the coin, after t seconds, is given by the following equation:

$h(t) = -16t^{2} + 72t + 100$

How long will it take the coin to reach the stream?

The stream is the ground level.

So the coin reaches the stream when h(t) = 0.

$h(t) = -16t^{2} + 72t + 100$

$-16t^{2} + 72t + 100 = 0$

Multiplying by (-1)

$16t^{2} - 72t - 100 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$16t^{2} - 72t - 100 = 0$

So

$a = 16, b = -72, c = -100$

$\bigtriangleup = (-72)^{2} - 4*16*(-100) = 11584$

$t_{1} = \frac{-(-72) + \sqrt{11584}}{2*16} = 5.61$

$t_{2} = \frac{-(-72) - \sqrt{11584}}{2*16} = -1.11$

Time is a positive measure, so we take the positive value.

It will take 5.61 seconds for the coin to reach the stream.

3 0

4 years ago

Compare 4.5x10^6 and 2.1x10^8 explain how you can compare them

Roman55 [17]

4.5 x 10^6 = 4,500,000
2.1 x 10^8 = 210,000,000

Therefore, 4.5 x 10^6 < 2.1 x 10^8

8 0

4 years ago

Reduce 18/45 to simplest form

nadya68 [22]

Answer:

2/5

Step-by-step explanation:

7 0

2 years ago

sveta [45]

For this case we have the following equation:
$d = \sqrt{\frac{3h}{2}}$
Where,
d: the distance they can see in thousands
h: their eye-level height in feet
For Kaylib:
$d = \sqrt{\frac{3(48)}{2}}$
$d=\sqrt{3(24)}$
$d=\sqrt{72}$
$d=6\sqrt{2}$
For Addison:
$d = \sqrt{\frac{3(85\frac{1}{3})}{2}}$
$d = \sqrt{\frac{256}{2}}$
$d=\sqrt{128}$
$d=8\sqrt{2}$
Subtracting both distances we have:
$8\sqrt{2} - 6\sqrt{2} = 2\sqrt{2}$
Answer:
$2\sqrt{2}$
B. 2√2 mi

6 0

3 years ago

Read 2 more answers