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barxatty [35]
3 years ago
10

Factor this expression completely.

Mathematics
1 answer:
mixer [17]3 years ago
3 0

Answer: B -7(3x-4)

-7×3x=-21x

-7×-4=28

I hope this is good enough:

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Hello can you please help me with this question
rusak2 [61]

Answer:

A

Step-by-step explanation:

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4 0
2 years ago
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A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat
konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles                    

First, we need to find b:    

a^{2} + b^{2} = h^{2}   (1)    

b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})

2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:  

0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}

\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h  

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0
3 years ago
A crane lifts a 425 kg steel beam vertically a distance of 66 m. How much work does the crane do on the beam if the beam acceler
Fiesta28 [93]
<span>The solution to the problem is as follows:

W=Fd=mad=425*1.8*66 =50490 J

Therefore, it takes </span><span>50490 J of work the crane will do to accelerate the beam upward at 1.8 m/s^2.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
6 0
3 years ago
Read 2 more answers
What is 5% of $30,000
ValentinkaMS [17]
30000= 100%
x=5%
30000/x=100/5
<span>(30000/x)*x=(100/5)*x
</span>30000=20*x
30000/20=x
x=1500 
5%of 30000 is 1500
7 0
3 years ago
Tammy has begun an exercise program. She worked out five days the first week for 28 minutes, 32 minutes, 21 minutes, 38 minutes
Luba_88 [7]
28 rounds up to 30.
32 rounds down to 30.
21 rounds down to 20.
38 rounds up to 40.
42 rounds down to 40.
30 + 30 + 20 + 40 + 40 = 160

Answer: C. 160 min
5 0
3 years ago
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