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barxatty [35]
3 years ago
10

Factor this expression completely.

Mathematics
1 answer:
mixer [17]3 years ago
3 0

Answer: B -7(3x-4)

-7×3x=-21x

-7×-4=28

I hope this is good enough:

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stock a changed by -5.70 during the the day stock b changed be 2 1/3 times that amount. how much did stock b change during the d
Romashka-Z-Leto [24]

Answer: -13.3

Step-by-step explanation:

2 1/3 * -5.70 = -13.3

7 0
4 years ago
There are 12 pieces of pie left over in the cafeteria. If 6 pieces are apple and 6 are cherry, what fraction of the remaining pi
ollegr [7]

Answer:

1/2

Step-by-step explanation:

If there are 12 pies, and 6 are apple, then 6/12 would represent the remaining apple pies.

Now simplify 6/12

It would be 1/2

7 0
3 years ago
Read 2 more answers
sarah went to the town carnival. she ended up staying for 1 hour and 35 minutes. if she left the carnival at 2:40 what time did
Alecsey [184]
I hope this helps you


2.40-1.35


1.05


1 hour 5 minutes
5 0
3 years ago
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CAN SOMEONE HELP ME IN THIS INTEGRAL QUESTION PLS
finlep [7]

Due to the symmetry of the paraboloid about the <em>z</em>-axis, you can treat this is a surface of revolution. Consider the curve y=x^2, with 1\le x\le2, and revolve it about the <em>y</em>-axis. The area of the resulting surface is then

\displaystyle2\pi\int_1^2x\sqrt{1+(y')^2}\,\mathrm dx=2\pi\int_1^2x\sqrt{1+4x^2}\,\mathrm dx=\frac{(17^{3/2}-5^{3/2})\pi}6

But perhaps you'd like the surface integral treatment. Parameterize the surface by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k

with 1\le u\le2 and 0\le v\le2\pi, where the third component follows from

z=x^2+y^2=(u\cos v)^2+(u\sin v)^2=u^2

Take the normal vector to the surface to be

\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial u}=-2u^2\cos v\,\vec\imath-2u^2\sin v\,\vec\jmath+u\,\vec k

The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:

\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|=u\sqrt{1+4u^2}

Then the area of the surface is

\displaystyle\int_0^{2\pi}\int_1^2\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\int_0^{2\pi}\int_1^2u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv

which reduces to the integral used in the surface-of-revolution setup.

7 0
3 years ago
Which set of numbers represents the lengths of the sides of a right triangle?
slega [8]
Using the Pythagorean theorem ~ a² + b² = c² ~, if this is true then the triangle is a right triangle.

a) 5² + 10² = 15²
    25 + 100 = 225 *FALSE*

b) 13² + 35² = 37²
     169 + 1225 = 1369 *FALSE*

c) 9² + 40² = 41²
    81 + 1600 = 1681 *TRUE*

d) 6² + 9² = 10²
    36 + 81 = 100 *FALSE*

The answer is C) 9, 40, 41.
5 0
3 years ago
Read 2 more answers
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