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zavuch27 [327]
3 years ago
7

It is known that 10% of the items produced by a certain machine end up having a flaw. If we select 7 items from the production l

ine, a) What is the probability that at least one of them has a flaw? Part b) What is the probability that exactly three of them has a flaw?
Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Step-by-step explanation:

p = 0.1, q = 0.9, n = 7

a) Use complementary probability.

P(at least 1) = 1 − P(0)

P(at least 1) = 1 − (0.9)⁷

P(at least 1) = 0.522

b) Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

P(3) = ₇C₃ (0.1)³ (0.9)⁴

P(3) = 0.023

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On Saturday, a local hamburger shop sold a combined total of 312 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold, How many hamburgers were sold on Saturday?

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Two Social Security numbers (see Exercise 8.12) match zeros if a digit of one number is zero iff the corresponding digit of the
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Answer:

Proved

Step-by-step explanation:

From the given parameters, we have:

n = 9 i.e. the length of each security numbers

r = 2 i.e. 2 security numbers

Required

In 513 security numbers, 2 must have matching zeros

To do this, we make use of Pigeonhole principle.

First, we calculate the number of all security numbers not having matching zeros.

Each of the 9 digits can be selected in 2 ways.

2 ways implies that each digit is either 0 or not

So, total selection is:

Total = 2^9

Total = 512

Apply Pigeonhole principle

The principle states that: suppose there are n items in m containers, where n>m, then there is at least one container that contains more than 1 item.

This means that if there are 512 security number without matching zeros, then there is 1 (i.e. 512 + 1) with matching zeros.

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