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luda_lava [24]
2 years ago
11

TRUE OR FALSE. Scale factor is the ratio of the lengths of two congruent sides of two similar polygons.

Mathematics
1 answer:
Rus_ich [418]2 years ago
8 0

Answer:

If two polygons are similar, then the ratio of the lengths of any two corresponding sides is called the scale factor. This means that the ratio of all parts of a polygon is the same as the ratio of the sides.Jan 21, 2020

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What is the area of a triangle that has a base of 10 ft and a height of 5 ft? A-15ft B-7.5ft C-25ft D-50ft​
weeeeeb [17]

Answer:

25

Step-by-step explanation:

formula for triangle is (b*h)/2=A

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The weight of two bags is 24/15kg . If the weight of one bag is 10/15. What will be the weight of other bag?
lys-0071 [83]
Weight of other bag would be 14/15 kg
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Elevii clasei a IV-a au fost la patinoar. Stiind ca numarul baietilor reprezinta jumatate plus 3 din numarul copiilor si ca numa
Shalnov [3]

Step-by-step explanation:

Fie x numărul de copii

f = 10 =\:fete

b\:=\:\frac{x}{2}\:+\:3

f\:+\:b\:=\:x

10\:+\:\frac{x}{2}\:+\:3\:=\:x

20\:+\:x\:+\:6\:=\:2x

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7 0
3 years ago
The ticket for ice hockey match was £14.50. the price has increased by 7%.
Serjik [45]
(14.50×7)/100 + 14.50
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Read 2 more answers
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
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