PQ // BC
then
Angle P = Angle B, A is common angle the two triangles are similar
AP/AB = AQ/AC
8/18 = 12/ AC
AC = 12 * 18/8 = 27 (your ans: D)
AQ + QC = AC
QC = AC - AQ = 27 - 12 = 15 (if it was required)
tan60 = y/8
y = s tan60 = 8sqrt(3) (B)
Next time, post each question separately.
If you draw more of those triangles, there will be 6 that can fit, so find area of 1 triangle and multiply it by 6. Write that number down and then do Pi r squared to find the area of the circle, then do circle area minus triangles area when you get that, divide it by 6. That is the area of the white region so then do Pi R squared again and then subtract the white area from that
Make an equation.
.1 X .5 X n = .25 X n - 30
.05n = .25n - 30
30 = .20n
150 = n
Answer:
Option B, 1
Step-by-step explanation:
tan 45° = 1/1 = 1
Answer:
SinA=5/1 3 CosA=12/13 tanA=5/12. SinC=12/13 CosC=5/13 and tanC=12/5
Step-by-step explanation:
Basically find the third side by Pythagorean theorem which would get you 13. So 13 is the hypotenuse. Remember these 3 formulas. Sin=Opposite/Hypotenuse Cos=Adjacent/hypotenuse and Tan=opposite/Adjacent. So for Sin a the opposite side to angle A is 5. The hypotenuse is always the same which would be 13. So Sin a is 5/13. For cos the side adjacent would be 12. So it is 12/13. *Note Hypotenuse cannot be considered the adjacent.