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Stells [14]
3 years ago
6

A typical roulette wheel used in a casino has 38 slots that are numbered 1, 2, 3, ... , 36, 0, 00, respectively The 0 and 00 slo

ts are colored green. Half of the remain ing slots are red and half are black. Also, half of the integers between 1 and 36 inclusive are odd, half are even, and 0 and 00 are defined to be neither odd nor even. A ball is rolled around the wheel and ends up in one of the slots; we assume that each slot has equal probability of 1/38, and we are interested in the number of the slot into which the ball falls.
a. Define the sample space S.
b. Let A = {0, 00}. Give the value of P(A).
c. Let B = {14, 15, 17, 18}. Give the value of P(B).
d. Let D = {x : x is odd}. Give the value of P(D).
Mathematics
1 answer:
Tema [17]3 years ago
8 0

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

For point a:

Space for results All possible outcomes are:

\to O = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,}

           17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, \\ 29, 30, 31, 32, 33, 34, 35, 36, 0, 00}

For point b:

\to P(A) = \frac{ \text{ \# of outcomes in A}}{ \text{ \# Total outcomes}} = \frac{2}{38} = 0.052

For point c:

\to P(B) = \frac{ \text{ \# of outcomes in B}}{\text{ \# Total outcomes}} = \frac{4}{38} = 0.105

For point d:

We consider that in D there are 18 elements (only Odd numbers in the range 1 to 36)

\to P(D) = \frac{ \text{\# of outcomes in D}}{\text{\# Total outcomes}} = \frac{18}{38} = 0.473

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Given: k= midpoint
hk=x+6
hj=4x-6

Remember midpoint cuts the segment hj in equal parts that means hk=kj and hk+kj=hj
hk+hk=hj
2hk=hj

2hk=hj
2 (x+6)=(4x-6)
2x+12=4x-6
2x-2x+12=4x-2x-6
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3 years ago
6. Fill in the smallest digit to make the number divisible by:
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Answer:

(i) 7164<u>0</u>, 32197<u>0</u>

(ii) 1<u>1</u>43, 47<u>2</u>05, <u>2</u>316

(iii) <u>1</u>428, 9<u>2</u>52, 721<u>2</u>

(iv) 2462<u>0</u>, 91<u>00</u>, 670<u>0</u>

(v) 1232<u>0</u>, 59<u>0</u>16, 4642<u>4</u>

Step-by-step explanation:

(i) In order for any number to be divisible by 5, its last digit must be <u>either 0 or 5</u>.

In this case, we should add a last digit, so we opt for <u>0</u> without any doubt since it gives a smaller number than <u>5</u> as the last digit: 71640 is smaller than 71645, the same way as 321970 is smaller than our second option, 321975.

(ii) If the sum of a number's digits gives a number divisible by 3, then the main number is also divisible by 3.

This means that we have to do some addition:

1_43: 1 + 4 + 3 = 8. Eight is not divisible by 3. But <u>9</u> is. So the smallest digit we can add for it to be divisible by three is <u>1</u>: <em>1143.</em>

47_05: 4 + 7 + 0 + 5 = 16. Since 16 is not, the next number that is divisible by 3 is 18, and therefore, the smallest digit we need here is <u>2</u>: <em>47205.</em>

_316: 3 + 1 + 6 = 10. Twelve is the next number divisible by 3, and that means <u>2</u> is the digit we choose: <em>2316.</em>

(iii) Only numbers that are divisible by both <u>2 and 3</u> are also divisible by 6.

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7 + 2 + 1 = 10 which is not divisible by 3 but 12 is. We will then choose to add <u>2</u>: <em>7212.</em>

(iv) A number is divisible by 4 only if the number that is formed by its two last digits is also divisible by 4..

2462_: Since we need to add a last digit, this should be easy. The smallest two-digit-number that starts with 2 and is divisible by four is <u>20</u>: <em>24620. </em>

91__: Here we need to add both of the two last digits, and this should be the easiest example! All numbers that end in <u>00</u>, meaning they have a round number of hundreds, are divisible by 4! Therefore our option is: <em>9100.</em>

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59_16: If we add a <u>0</u> here, the last three digits form the number 016, which is divisible by 8. Our choice is again zero: <em>59016.</em>

4642_: Unfortunately, 420 is not divisible by 8. The next number closest to 420 and which is divisible by 8 is 424. Its division by 8 gives 53. Therefore we should add <u>4</u>: <em>46424.</em>

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