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Stells [14]
3 years ago
6

A typical roulette wheel used in a casino has 38 slots that are numbered 1, 2, 3, ... , 36, 0, 00, respectively The 0 and 00 slo

ts are colored green. Half of the remain ing slots are red and half are black. Also, half of the integers between 1 and 36 inclusive are odd, half are even, and 0 and 00 are defined to be neither odd nor even. A ball is rolled around the wheel and ends up in one of the slots; we assume that each slot has equal probability of 1/38, and we are interested in the number of the slot into which the ball falls.
a. Define the sample space S.
b. Let A = {0, 00}. Give the value of P(A).
c. Let B = {14, 15, 17, 18}. Give the value of P(B).
d. Let D = {x : x is odd}. Give the value of P(D).
Mathematics
1 answer:
Tema [17]3 years ago
8 0

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

For point a:

Space for results All possible outcomes are:

\to O = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,}

           17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, \\ 29, 30, 31, 32, 33, 34, 35, 36, 0, 00}

For point b:

\to P(A) = \frac{ \text{ \# of outcomes in A}}{ \text{ \# Total outcomes}} = \frac{2}{38} = 0.052

For point c:

\to P(B) = \frac{ \text{ \# of outcomes in B}}{\text{ \# Total outcomes}} = \frac{4}{38} = 0.105

For point d:

We consider that in D there are 18 elements (only Odd numbers in the range 1 to 36)

\to P(D) = \frac{ \text{\# of outcomes in D}}{\text{\# Total outcomes}} = \frac{18}{38} = 0.473

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Answer:

b. x=\frac{5\pi}{6}

Step-by-step explanation:

The given function is

\sec x=-\frac{2\sqrt{3} }{3},\:\:for\:\:\frac{\pi}{2}\le x \le \pi

Recall that the reciprocal of the cosine ratio is the secant ratio.

This implies that;

\frac{1}{\cos x}=-\frac{2\sqrt{3} }{3}

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Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal
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Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

\dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{49}

Or, \dfrac{1}{y + 49} + \dfrac{1}{y} = \dfrac{1}{49}

Or, \dfrac{y + 49 + y}{y^{2} + 49 y } = \dfrac{1}{49}

Or, 2 y + 49 = \dfrac{y^{2}+49y }{19}

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = \frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or,  y = \frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}

Or, y = \frac{- 1 \pm \sqrt{121+3724}}{2}

or, y = \frac{- 1 \pm \sqrt{3845}}{2}

or, y = \frac{- 1 \pm 62.008}{2}

∴   y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0
3 years ago
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