1) Factor out the coefficient 2: 2x^2+12x=4 => 2(x^2 + 6x) = 4
2) Complete the square of x^2 + 6x: x^2 + 6x + 9 - 9. Then:
2(x^2 + 6x + 9 - 9) = 4
3) Rewrite the square as the square of a binomial:
2( [x+3]^2 - 9) = 4, or
2([x+3]^2) = 22, or
2( [x+3]^2 ) - 22 = 0
The value of q is -22.
First lets get 3% into decimal form.
3% is 3/100 = 0.03
Now multiply 0.03 by 47000 to get how much extra money she was going to get.
47000 * 0.03 = 1410
Now we just add
47000 + 1410 = 48410 is what she was going to make in 2012
Another way to do this is
(47000)(1+0.03) = 48410
you would use (1+0.03) which tells you she increased in pay.
The valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b
<h3>How to determine the valid exclusion?</h3>
The expression is given as:
8ab^2x/4a^2b - 8ab^2
Set the denominator to 0
4a^2b - 8ab^2 = 0
Divide through by 4ab
a - 2b = 0
Add 2b to both sides
a = 2b
Hence, the valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b
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Answer:
Step-by-step explanation:
Given the function f(x)=6+x
F(x) is dependent on x,
When x=1
f(x)=6+x
f(x)=6+1,
f(x)=7
When x=2
f(x)=6+x
f(x)=6+2
f(x)=8.
This will continue like this till we get to x=15
So when x=15
We will substitute x=15 into the function f(x)
f(x)=6+x
f(x)=6+15
f(x)=21
Then, the answer is 21.
Answer:
Top row: [1 0 0 1000]
Middle row: [0 1 0 300]
Bottom Row: [0 0 1 0]
Step-by-step explanation:
To put it in RREF form, you need to have only 1's in a diagonal and 0's both top and bottom of the 1's. To get to the forms, you need to multiply and add rows together to solve for RREF.