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AlexFokin [52]
3 years ago
5

Find the linear that is the best fit for the given data. Round decimals values to the nearest hundredth, if necessary

Mathematics
1 answer:
belka [17]3 years ago
3 0
The linear least squares regression will have a slope of:

m=(nΣxy-ΣxΣy)/(nΣx^2-ΣxΣx)

m=(5*2078-30*281)/(5*220-30*30)

m=1960/200

m=9.8

and a y-intercept of:

b=(Σy-mΣx)/n

b=(281-9.8*30)/5

b=-2.6

So the line of best fit is:

y=9.8x-2.6
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Pls help :( I’m so stuck in this
hodyreva [135]

Answer:

  • 99.6 ft²

Step-by-step explanation:

<u>Three faces are equal triangles with:</u>

  • base = 8 units, height = 6 ft

<u>The base is a triangle with:</u>

  • base = 8 ft, height = 6.9 ft

<u>Surface area is sum of areas of 4 faces:</u>

  • S = 3*(1/2*8*6) + 1/2*8*6.9 = 99.6 ft²
8 0
3 years ago
Read 2 more answers
For which values of the variables the following equality is true?
Ilia_Sergeevich [38]

Answer:

For The value of a = 0 and c = 0 , The given expression equality is true  

Step-by-step explanation:

Given expression as :

\frac{3a^{2}+ac+2c-6a}{3a - c} = a - 2

Or, 3 a² + ac + 2 c - 6 a = ( a - 2 ) × ( 3 a - c )

Or, 3 a² + ac + 2 c - 6 a =  3 a² - ac - 6 a + 2 c

Or, (  3 a² + ac + 2 c - 6 a ) - ( 3 a² - ac - 6 a + 2 c ) =0

Or, ( 3 a² - 3 a² ) + ( ac + ac ) + ( 2 c - 2 c ) + ( - 6 a + 6 a ) = 0

or,  0 + 2 ac + 0

Or, 2 ac = 0

∴  a =0  and c = 0

Hence For The value of a = 0 and c = 0 , The given expression equality is true  .  Answer

6 0
3 years ago
What is lim x→3 x^2 - x - 6/ x - 3
Kisachek [45]
<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, \frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2

Allowing us to say,

\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

5 0
3 years ago
A circular foundation has a radius of 9.4 feet. Find it's diameter and circumference to the nearest tenth
Ganezh [65]
The diameter of the circular foundation would be 18.8 feet, and the circumference would be 59.1 feet.
5 0
3 years ago
Read 2 more answers
Stan worked 4 years less than Marco.This year Stan has worked 29 years.If b is how long Marco worked, the equation b - 4 = 29 re
MA_775_DIABLO [31]

Answer:

Add 4 on both sides.

In the equation there is a -4.

If -4+4=0, that is how you would get rid of the -4.

But, you need to add 4 to 29 to really get rid of the -4.

So, 29+4 is 33.

b=33

6 0
3 years ago
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