d = 16.76 inches
Step-by-step explanation:
We can extend the definition of the Pythagorean theorem to 3-dimensions:

Let x = 10 in
y = 10 in
z = 9 in


Answer:
the left side of the line
Step-by-step explanation:
Answer: The minimum reliability for the second stage be 0.979.
Step-by-step explanation:
Since we have given that
Probability for the overall rocket reliable for a successful mission = 97%
Probability for the first stage = 99%
We need to find the minimum reliability for the second stage :
So, it becomes:
P(overall reliability) = P(first stage ) × P(second stage)

Hence, the minimum reliability for the second stage be 0.979.