Answer:
a 1 over 25
Step-by-step explanation:
Problem Statement:
What is the value of 
?
To solve this problem, we must familiarize ourselves with the concept of exponents and rules that guides them.
Exponents are used by scientists to report higher orders of a number.
Such large and often recurring expression is usually made up of a base and an exponent value.
The exponent value is the power of the base; for example, 4³ has 4 as its base and 3 as the exponent.
Several rules guides solving an exponent, to this problem, the most applicable one is :
= 
= 
= 
= 
Therefore the solution is 1 over 25
So with the 10% discount, thats 45$, adding tax, that's <span>$47.70.</span>
3 divided by 8 is .375
14 divided by .375 is 37.3 repeating
and the fraction for that is 112/3
we know that
1 ft is equal to 12 in
1 cubic yard is equal to 27 cubic feet
Step 1
<u>Find the area of the circular border of uniform width around the pool</u>
Let
x---------> the uniform width around the pool
we know that
The diameter of the circular pool measures 10 feet
so
the radius r=5 ft
the area of the circular border is equal to
![A=\pi *(5+x)^{2}- \pi *5^{2} \\A= \pi *[(x+5) ^{2}-5^{2} ] \\ A= \pi * [x^{2} +10x]](https://tex.z-dn.net/?f=A%3D%5Cpi%20%2A%285%2Bx%29%5E%7B2%7D-%20%5Cpi%20%2A5%5E%7B2%7D%20%5C%5CA%3D%20%5Cpi%20%2A%5B%28x%2B5%29%20%5E%7B2%7D-5%5E%7B2%7D%20%5D%20%5C%5C%20A%3D%20%5Cpi%20%2A%20%5Bx%5E%7B2%7D%20%2B10x%5D)
step 2
volume of the concrete to be used to create a circular border is equal to
V=1 yd^{3}-------> convert to ft^{3}
V=27 ft^{3} -------> equation 1
the depth is equal to 4 in-------> convert to ft
depth=4/12=(1/3) ft
volume of the concrete to be used to create a circular border is also equal to
V=Area of the circular border*Depth
![V= \pi * [x^{2} +10x]*(1/3)](https://tex.z-dn.net/?f=V%3D%20%5Cpi%20%2A%20%5Bx%5E%7B2%7D%20%2B10x%5D%2A%281%2F3%29)
-------> equation 2
equate equation 1 and equation 2
![27=\pi * [x^{2} +10x]*(1/3) \\ x^{2} +10x- \frac{81}{\pi }=0](https://tex.z-dn.net/?f=27%3D%5Cpi%20%2A%20%5Bx%5E%7B2%7D%20%2B10x%5D%2A%281%2F3%29%20%5C%5C%20x%5E%7B2%7D%20%2B10x-%20%5Cfrac%7B81%7D%7B%5Cpi%20%7D%3D0)
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is the point
x=2.126 ft
therefore
<u>the answer is</u>
The uniform width around the circular pool border is 2.126 ft
where: a is the length of the major axis and b is the length of the minor axis.
Thus,
