We know there’s 660 boxes and each box called for 3 eggs, therefore:
660=3X
when divide both sides by 3 to isolate the x, which will tell us the amount of eggs used…
660/3 = 220
Answer:
The Car.
Step-by-step explanation:
We need to find the unit rate for each vehicle to figure out who is traveling faster or slower.
Car: 600/20 = 30 ft per second
Motorcycle: 300/12 = 25 ft per second
So, the Car is faster
(
+ 4)( - 4)
To solve this question you must FOIL (First, Outside, Inside, Last) like so
First:
(x^2 + 4)(x^2 - 4)
x^2 * x^2
x^4
Outside:
(x^2 + 4)(x^2 - 4)
x^2 * -4
-4x^2
Inside:
(x^2 + 4)(x^2 - 4)
4 * x^2
4x^2
Last:
(x^2 + 4)(x^2 - 4)
4 * -4
-16
Now combine all the products of the FOIL together like so...
x^4 - 4x^2 +4x^2 - 16
Combine like terms:
x^4 - 4x^2 +4x^2 - 16
- 4x^2 +4x^2 = 0
x^4 - 16 <<<This is your answer
Hope this helped!
~Just a girl in love with Shawn Mendes
More than one liter because it only depends how bog your sink is...I believe it is more than one liter
Siras ! Don't try to picture this all in your head !
You'll wear out your brain.
You MUST sketch it on a piece of paper.
Draw an x-axis and a y-axis, then draw the two circles.
I'm drawing myself a picture right now, and I'm
supposed to be some kind of a genius.
a). In order to move Circle-Q so that both centers are
at the same point, you need to move the center of Q
4 units down and 2 units to the right.
When you do that, you'll have the little circle inside the
big circle, with their centers both at the same place.
b). The radius of Q is 2.
The radius of P is 20.
What do you have to multiply 2 by, in order to get 20 ?
THAT's the scale factor to dilate Q so that it has the same
radius as P.
When you do that, suddenly it'll look like you only have one circle
on the paper ... they'll both have the same radius and their centers are
at the same place, so you can't tell them apart.
c). All circles are similar !
I went online (you could easily go there too). I searched the question
"Are circles similar ?" and a lot of interesting stuff came up. (you could
do that too). I saw a lot of ways to prove that all circles are similar.
The best one says:
Two figures are "similar" if you can make one of them
exactly fit on top of the other one (make them congruent)
with translations and dilations.
You just did that with P and Q !
-- Translation is moving them around.
You moved Q and put the centers of both circles at the same place.
-- Dilation is blowing it up or blowing it down, so its size changes
but its shape doesn't change.
You blew Q up so that it had the same radius as P.
Then the two circles exactly fit over/under each other.
So the two circles are similar.
