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Naddik [55]
3 years ago
12

How many of degrees are in an angle that turns through 1/4 of a circle

Mathematics
1 answer:
zavuch27 [327]3 years ago
7 0
1/4 turn = 90 degrees 
<span>1/2 turn = 180 degrees </span>
<span>3/4 turn = 270 degrees </span>
<span>1 full turn = 360 degrees </span>

<span>:)</span>
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Find the angle of least nonnegative​ measure, θC​, that is coterminal with θ=<br> 9π/4.
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Answer:

  θC = π/4

Step-by-step explanation:

To find the desired angle, subtract multiplies of 2π until the angle is in the desired range.

  9π/4 -2π = (9-8)π/4 = π/4

The angle θC = π/4 is coterminal with θ = 9π/4.

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MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
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Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

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